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3 years ago

There are 14 red marbles and 20 blue marbles in a bag of marbles.

Mathematics

2 answers:

sergeinik [125]3 years ago

6 0

Answer:

7:10

Step-by-step explanation:

14/20= 7/10

pantera1 [17]3 years ago

6 0

Answer: 7:10 because it is what it is.

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The following data represent the monthly phone use, in minutes, of a customer enrolled in a fraud prevention program for the pas

Illusion [34]

Answer:

The answer is "717.25 minutes".

Step-by-step explanation:

In this question first, we arrange the value in ascending order that are:

307,311,321,322,354,363,377,406,425,435,461,464,474,499,505,513,517,534,548

The median is always in an orderly position that is $= \frac{(n+1)}{2}$ .

$\to \frac{(n+1)}{2} = \frac{(20+1)}{2} = 10.5$ position orders

$10^{th} \ and \ 11^{th}$ place an average of observations so, the

$Average = \frac{(425 +435)}{2} = \frac{(860)}{2} =430$

Because as medium stands at 10.5 that median is as below 10 are greater than the level.

$Q_1$ often falls throughout the ordered BELOW average is $= \frac{(n+1)}{2}$ place.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered position

Average $5^{th} \ and \ 6^{th}$ location findings

$Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5$

In $= \frac{(n+1)}{2}$ the ordered place, Q3 always falls ABOVE the median.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered At median ABOVE

Consequently $Q_3$ falls between $5^{th} \ and \ 6^{th}$ ABOVE the median position

$15^{th}\ and \ 16^{th}$ place average of observations

$\to Q_3 = \frac{(499+505)}{2}=\frac{(1004)}{2} = 502$

$\to IQR = Q_3 - Q_1= 502-358.5= 143.5$

$\to \text{Upper fence} = Q_3 + 1.5 \times IQR= 502 + 1.5 \times 143.5 = 717.25$

4 0

2 years ago

Ellen is playing a video game in which she captures butterflies. There are 6 butterflies onscreen, but the number of butterflies

Anna11 [10]

Answer:

(2 x 4) - 8

Step-by-step explanation:

4 0

2 years ago

At an airport, it cost $7 to park for up to one hour and $5 per hour for each additional hour. Let x represent the number of hou

RUDIKE [14]

C(x)=7+5x Should be the correct answer

4 0

3 years ago

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In a jewelry store, rings make up 5/9 of the inventory. Earrings make up 4/15 of the inventory. How many times greater is the ri

monitta

Make the fractions have common denominators.

rings 5 / 9 * 5/5 = 25/45
earrings 5/15 * 3/3 = 15/45

So, now we can compare 25 to 15. 25 is 5/3 bigger than 15.
or the ring inventory is 1.666666666... times greater than the earring inventory.

8 0

3 years ago

Can u pls help me with this question

blsea [12.9K]

Answer:

no I can't srry tdjfjfzkhdzlhfzljgxjghc,lhfzjfzlhdzlhfzulf

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2 years ago

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