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eimsori [14]
3 years ago
6

There are 14 red marbles and 20 blue marbles in a bag of marbles.

Mathematics
2 answers:
sergeinik [125]3 years ago
6 0

Answer:

7:10

Step-by-step explanation:

14/20= 7/10

pantera1 [17]3 years ago
6 0

Answer: 7:10 because it is what it is.

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Vertex of f(x) = 1/2(x-2)^2-3
AlekseyPX
Vertex is (2,-3). H (which is 2) sign is always opposite and k stays the same
3 0
3 years ago
What is the correct answer to this please
murzikaleks [220]
I am sorry if i am wrong but i keep getting 6,4
3 0
3 years ago
A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

6 0
3 years ago
A pack of red pens can be divided into equal shares among 3, 5, 6 and 9 teachers with no pen left over?
Ugo [173]

Answer:

90 red pens

Step-by-step explanation:

we need to find the least common multiple of the numbers 3 , 5 , 6 , 9

6 = 2 × 3

9 = 3²

then

LCM(3,5,6,9) = 2×5×3² = 2×5×9 = 90

The number 90 can be divided into 3 ,5 ,6 ,9 with no remainder

Therefore the pack must have 90 pens or a multiple of 90

For example 180 , 270 ...

7 0
2 years ago
I report if u guess or answer randomly. Which confidence level would produce the widest interval when estimating the mean of a p
kap26 [50]

Answer:

B. 61%

Step-by-step explanation:

When we have the standard deviation of a sample, we use the t-distribution.

The width of an interval is related to the margin of error, which is given by the following equation:

M = T*s

In which T is related to the confidence level(and the sample size) and s is the standard deviation of the sample. Higher confidence levels have higher values of T.

A higher margin of error means that the interval is wider. To have a higher margin of error, we desire a higher value of T, which is achieved with a higher confidence level.

So the correct answer is:

B. 61%

5 0
3 years ago
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