Need Help pleasee.. I have attached the question below.. For the quick and correct answer I will give 10 points and brainliest

Mathematics

1 answer:

kirill [66]3 years ago

5 0

A equals 3
Equation is g(x)=3f(x)

What i did is notice the y intercept is at 3 so I plugged in x=0 into the parent equation and got f(0)=1

So to get this equation to the y=3 intercept which is the g function, you have to multiply it by 3

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A bag contains 5 blue balls, 4 red balls, and 3 orange balls. If a ball is picked from the bag at random, what is the probabilit

Marysya12 [62]

Answer:

There is a 41.7% chance that you got a blue ball.

Step-by-step explanation:

Total number of blue balls/Total number of balls x 100 = Chance of getting a blue ball

=> 5/12 x 100
=> 5/6 x 50
=> 5/3 x 25
=> 125/3
=> 41.7

Hence, there is a 41.7% chance that you got a blue ball.

Hoped this helped.

$BrainiacUser1357$

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2 years ago

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Pls help asap giving brainlist if it lets me

ra1l [238]

Answer:

F and D

Step-by-step explanation:

When a negative number is multiplied by a positive number, the result is a negative number. When a negative number is multiplied by another negative number, the result is positive.

4 0

2 years ago

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I really need to know how long it takes the large pipe on its own

Andreyy89

s = hours it takes the small pipe on its own.

L = hours it takes the large pipe on its own.

we know the small pipe can do it in 11 hours total, so s = 11, so, how much of the whole job has the small done in 1 hour only?

well, if it takes 11 hours to do the whole thing, in 1 hour it has done only 1/11 of the whole job.

we know both pipes working together can do it in 6 hours flat. So in 1 hour only, both of them have done only 1/6 of the whole thing.

in that 1 hour, how much has the large one done? well, it has only done 1/L of the job.

$\bf \stackrel{\textit{how much has it been done by both in 1 hour}}{\stackrel{\stackrel{small}{rate}}{\cfrac{1}{s}}+\stackrel{\stackrel{large}{rate}}{\cfrac{1}{L}}~~=~~\stackrel{job}{\cfrac{1}{6}}} \\\\\\ \cfrac{1}{11}+\cfrac{1}{L}=\cfrac{1}{6}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{66L}}{6L+66=11L}\implies 66=5L \\\\\\ \cfrac{66}{5}=L\implies 13\frac{1}{5}=L\impliedby \textit{13 hours and 12 minutes}$