Answer:
Quality of service (QOS).
Explanation:
In recent computer networking, the convergence of voice, video and text data packet has been made possible. There is no need for a dedicated network for a particular type of packet.
QOS or quality of set is a service rendered to voice or audio packets in VoIP phones to enhance communication.
The email is a digital mailing system that can be used to send all three packets. It enjoys the QOS as voice packets. It is given high preference for transmission and uses the TCP protocol to transmit data reliably.
Answer:
Interval Recording
Explanation:
According to my research on different data collection methods, I can say that based on the information provided within the question this method of data collection is called Interval Recording. This refers to the process of collecting different pieces of data from different parts of the same interview or study. Which is what Mrs. Golden is doing.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
D)Exhaustion
Hope this helps
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
I believe the correct answer is choice D. Making a law.
I don't believe the scientific method says anything about making a law.
I hope this helps you and have a great day!
