C. Send it to the recycle bin and empty the recycle bin
Answer:
The symbols may or may not have meaning, but the machine does not need to know how the symbols are interpreted in order to manipulate the symbols in the right way.
Explanation:
The computer can change the symbols in the case when the computer understand but in actual following the cut-paste rules without having any understanding this is because the symbols might be have meaning or not but if we talk about the machine so actually they dont know how the symbols are interpreted and how it can be used so that it can be change in the accurate way
Indentation and alignment are very noticeable on a printed page, so you will probably want to set the tab stops in your document precisely how you want them.
Its false nothing comes up when u press that key
Answer:
public class MagicSquare {
public static void main(String[] args) {
int[][] square = {
{ 8, 11, 14, 1},
{13, 2, 7,12},
{ 3, 16, 9, 6},
{10, 5, 4, 15}
};
System.out.printf("The square %s a magic square. %n",
(isMagicSquare(square) ? "is" : "is not"));
}
public static boolean isMagicSquare(int[][] square) {
if(square.length != square[0].length) {
return false;
}
int sum = 0;
for(int i = 0; i < square[0].length; ++i) {
sum += square[0][i];
}
int d1 = 0, d2 = 0;
for(int i = 0; i < square.length; ++i) {
int row_sum = 0;
int col_sum = 0;
for(int j = 0; j < square[0].length; ++j) {
if(i == j) {
d1 += square[i][j];
}
if(j == square.length-i-1) {
d2 += square[i][j];
}
row_sum += square[i][j];
col_sum += square[j][i];
}
if(row_sum != sum || col_sum != sum) {
return false;
}
}
return d1 == sum && d2 == sum;
}
}
