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Phoenix [80]
3 years ago
15

Josefina lives near a duck pond. She wants to know how many ducks use the pond. She places leg bands on 12 ducks one day. A week

later, she examines 20 ducks and finds that 3 of them have leg bands. About how many ducks use the pond? 80 29 160 50
Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0

Answer:

80

Step-by-step explanation:

This is calculated as:

(Number of ducks with bands × Number of examined ducks)/ Number of ducks found with leg band

= Number of ducks with bands = 12 ducks

Number of examined ducks = 20 ducks

Number of ducks found with leg band = 3 ducks

Hence:

12 × 20/3

= 240/3

= 80 ducks

Therefore, 80 ducks used the ponds

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The number of patients treated at Dr. Artin’s dentist office each day was recorded for nine days. These are the data: 6, 6, 6, 5
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Answer:

D) 5.6, 6, 6, 1

Step-by-step explanation:

Before we start solving this problem, we need to first rearrange the provided data from smallest to greatest, so we get:

5, 5, 5, 5, 6, 6, 6, 6, 6

now we can find the mean. The mean is nothing but the average of the provided values, so we need to add them and then divide them into the total amount of data:

mean=\frac{5+5+5+5+6+6+6+6+6}{9}=5.6

next, in an odd number of data, the median is the middle number when written in order. In this case the middle number (the one in the position 5) is 6, so:

median=6

the mode will tell you what is the value that has the greatest number of occurrencies. This is the number that appears the most on our list.

Mode=6

and the range is the difference between the greatest value and the smallest value:

Range=6-5=1

so the answer is D.

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3 years ago
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3 years ago
What number replaces the ◊?
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A building's basement is 15 feet below ground. The building is square shaped with side lengths of 60 feet. If the height of the
bezimeni [28]
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Activity 2. Find the equation of the line using Two-Point form,
jasenka [17]

Answer:

1) equation of line is: y-3=0

2) equation of line is: \mathbf{y-3=-\frac{1}{2}(x-4)}

3) equation of line is: \mathbf{y+3=-\frac{4}{3}(x-3}

4) equation of line is: \mathbf{y-2=-2(x-2)}

Step-by-step explanation:

We need to find the equation of the line using Two-Point form.

The general equation of two-point form is: y-y_1=m(x-x_1) where m is slope.

The formula used to calculate slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

1. (1,3) and (-2,3)

First finding slope

We have: x_1=1, y_1=3, x_2=-2, y_2=3

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{3-3}{-2-1}\\Slope=\frac{0}{-3}\\Slope=0\\

So, equation of line will be:

Using slope m=0 and point (1,3)

y-y_1=m(x-x_1)\\y-3=0(x-1)\\y-3=0\\

So, equation of line is: y-3=0

2. (4,3) and (6,2)

First finding slope

We have:x_1=4, y_1=3, x_2=6, y_2=2

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-3}{6-4}\\Slope=\frac{-1}{2}\\

So, equation of line will be:

Using slope m=\frac{-1}{2} and point (4,3)

y-y_1=m(x-x_1)\\y-3=\frac{-1}{2}(x-4)\\y-3=-\frac{1}{2}(x-4)

So, equation of line is: \mathbf{y-3=-\frac{1}{2}(x-4)}

3) (3,-3) and (0,1)

First finding slope

We have: x_1=3, y_1=-3, x_2=0, y_2=1

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{1-(-3)}{0-3}\\Slope=\frac{1+3}{-3}\\Slope=-\frac{4}{3}\\

So, equation of line will be:

Using slope m=-\frac{4}{3} and point (3,-3)

y-y_1=m(x-x_1)\\y-(-3)=-\frac{4}{3}(x-3)\\y+3=-\frac{4}{3}(x-3)\\

So, equation of line is: \mathbf{y+3=-\frac{4}{3}(x-3)}

4) (2,2) and (4,-2)

First finding slope

We have: x_1=2, y_1=2, x_2=4, y_2=-2

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-2-2}{4-2}\\Slope=\frac{-4}{2}\\Slope=-2\\

So, equation of line will be:

Using slope m=-2 and point (2,2)

y-y_1=-2(x-x_1)\\y-2=-2(x-2)\\

So, equation of line is: \mathbf{y-2=-2(x-2)}

3 0
3 years ago
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