Using the expected value, it is found that the mean of the distribution equals $0.1.
- The expected value, which is the mean of the distribution, is given by <u>each outcome multiplied by it's probability</u>.
The probabilities of <u>each outcome</u> are:
- .0000001 probability of earning $1,000,000.
- .9999999 probability of earning $0.
Thus, the mean is given by:

Thus showing that the expected value is $0.1.
A similar problem is given at brainly.com/question/24855677
Answer:
If you've learnt sin(A+B) = sinAcosB + cosAsinB,
sin(4u)
= sin(2u+2u)
= sin(2u)cos(2u) + cos(2u)sin(2u)
= 2 sin(2u) cos(2u).
Answer:
Let the number be x
3.06% = 0.0306
The above statement is written as
0.0306x = 0.86
Divide both sides by 0.0306
x = 0.86/0.0306
<h2>x = 28.10</h2>
Hope this helps you
Its false because it can't repeat in a set.