Using the normal distribution, it is found that due to the greater z-score, Stewart caught the longer fish relative to the same specie.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
To find who caught the longer fish relative to the same specie, we need to find out who had the higher z-score.
Stewart caught a bluefish with a length of 322 mm, hence the parameters are as follows:

The z-score is:


Z = 1.41
Gina caught a pompano with a length of 176 mm, hence the parameters are as follows:

The z-score is:


Z = 0.75.
Hence Stewart caught the longer fish relative to the same specie.
More can be learned about the normal distribution at brainly.com/question/4079902
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Answer:
1) C = $25 + $40 × h
2) The domain for the ≠unction is 0 ≤ h ≤ ∞
The range for the function is 25 ≤ C ≤ ∞
3) Continuous
Step-by-step explanation:
1) The given parameters are;
The base fee charged = $25
The amount charged for labor = $40/hour
The total cost for h number of hours is C = $25 + $40 × h
2) The domain for the ≠unction is 0 ≤ h ≤ ∞
The range for the function is 25 ≤ C ≤ ∞
3) The situation is continuous because the different input values of h can be infinite (from o to infinity)
Answer:
c
Step-by-step explanation:
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Using a graphing calculator you can find that the maximum is 1038, so the profit starts to decline at the t value for <span>1038</span>, which is 31
Answer:
<h2>y = 3x - 3</h2>
Step-by-step explanation:
The slope-intercept form of an equation of a line:

<em>m</em><em> - slope</em>
<em>b</em><em> - y-intercept</em>
<em />
We have the slope <em>m = 3</em>, and the point <em>(2, 3)</em>.
Put the value of slope and the coordinates of the given pint (x = 2, y = 3) to the equation of a line:

<em>subtract 3 from both sides</em>

Finally:
