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mash [69]
3 years ago
13

What is 1 3/5 as a mixed number

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0

Answer:

8/5

Step-by-step explanation:

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A coin is tossed 10 times, and lands on tails 70% of the time. Which statement is true?
devlian [24]

Answer: If Answer "B" is supposed to say, "The coin landed on tails 7 out of 10 times" then thats the answer.

Step-by-step explanation:

If the coin landed on tails 70% of the time, then the answer is B

8 0
3 years ago
4. A sports car accelerates from rest to a final velocity of 64 m/s at a rate of 12.3
Ivanshal [37]

Answer:

t = 5.2\ s

Step-by-step explanation:

Given

a= 12.3m/s^2 --- acceleration

v = 64m/s --- final velocity

u =0m/s --- initial velocity (it is 0, because the car starts from rest)

Required

Determine the time taken

This will be solved using Newton's first equation of motion:

v = u + at

Substitute values for v, u and a

64 = 0 + 12.3*t

64 = 12.3t

12.3t = 64

Make t the subject

t = \frac{64}{12.3}

t = 5.2\ s

<em>Hence, the time taken is approximately 5.2 seconds</em>

6 0
3 years ago
Y’all I’m so bored! Here’s some free points
artcher [175]

Answer:

thanks

Step-by-step explanation:

appreicate it !

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8 0
3 years ago
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If (a^2 + b^2) (x^2 +y^2) = (ax + by )^2 then which relation is true?​
NikAS [45]

Answer:

Step-by-step explanation:

Hello,

Let's develop both expressions and try to re factorise.

\forall (a,b,x,y) \in \mathbb{R}^4  \\ \\ (a^2+b^2)(x^2+y^2)=(ax+by)^2\\ \\(ax)^2+(ay)^2+(bx)^2+(by)^2=(ax)^2+(by)^2+2(ax)(by)\\ \\ (ay)^2+(bx)^2-2(ay)(bx)=0\\ \\ (ay-bx)^2=0\\ \\ ay-bx=0\\ \\ \boxed{\sf \bf ay=bx}

Thanks

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3 years ago
Triangle ABC is formed by the vertices A(1,2,-1), B(-3,-6,2)and C(3,-2,0).
Vesnalui [34]

Answer:

Point D: (0,-4, 1 )

<em>d</em> = √41

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Pre-Calculus</u>

  • Midpoint Formula [3D]: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}, \frac{z_1+z_2}{2} )
  • Distance Formula [3D]: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point A(1, 2, -1)

Point B(-3, -6, 2)

Point C(3, -2, 0)

<u>Step 2: Find Point D</u>

Simply plug in your coordinates B and C into the midpoint formula to find midpoint

  1. Substitute [MF]:                    (\frac{-3+3}{2},\frac{-6-2}{2}, \frac{2+0}{2} )
  2. Add/Subtract:                       (\frac{0}{2},\frac{-8}{2}, \frac{2}{2} )
  3. Divide:                                  (0,-4, 1 )

<u>Step 3: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates A and D into the distance formula to find distance <em>d</em>

  1. Substitute [DF]:                    d = \sqrt{(0-1)^2+(-4-2)^2+(1+1)^2}
  2. Subtract/Add:                       d = \sqrt{(-1)^2+(-6)^2+(2)^2}
  3. Exponents:                           d = \sqrt{1+36+4}
  4. Add:                                      d = \sqrt{41}
5 0
3 years ago
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