Answer:
Step-by-step explanation:
Elapsed Time (Seconds) Distance Travelled (Feet)
1 6.2
2 12.4
3 18.6
4 24.8
To form an equation, we first need to check whether the changing rate is a linear or non-linear.
A linear rate would give the same changing rate every one second traveled
Distance traveled between second 1 and second 2 = 12.4 - 6.2 = 6.2
Distance traveled between second 2 and second 3 = 18.6 - 12.4 = 6.2
Distance traveled between second 3 and second 2 = 24.8 - 18.6 = 6.2
Since the increase is the same every second, 6.2 feet, our equation would be the linear equation which is in the form y = mx + c
Where 'm' represents the gradient (changing rate) and c represents the distance traveled when the time is zero, which is also zero
n = 1 ⇒ d = 6.2
n = 0 ⇒ d = 6.2 - 6.2 = 0
We have m = 6.2 and c = 0
The equation is f = 6.2n
Answer: Option 3
A simple equation you could use to find the score James got on his first test would be x+18=86 where x is the score he received on the first test.
<u>Solution</u><u />
x+18=86
-18-18
x=68
With this in mind, using the equation we created, we know that James received 68 points on his first test.
Answer:
See Explanation
Step-by-step explanation:
Given
Analyzing Lin's
<em>This isn't a solution because </em>
<em />
Analyzing Elena's
Divide through by 5
Hence;
<em>Going by the analysis above; only Elena's move will lead to a solution</em>
Answer:
If Franco wants to double the volume, he must multiply the radius and height of the original cone by ![\sqrt[3]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D)
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube
Let
z-----> the scale factor
x----> the volume of the larger cone
y----> the volume of the original cone
so
we have
substitute and solve for the scale factor
![z=\sqrt[3]{2}](https://tex.z-dn.net/?f=z%3D%5Csqrt%5B3%5D%7B2%7D)
------> the scale factor
If Franco wants to double the volume, he must multiply the radius and height of the original cone by
