48 c atoms
88 h atoms
44 o atoms
Answer:
7/12
Step-by-step explanation:
The nth term Tₙ = n(n-4) /n+3.
The 1st term T₁ = 1(1 - 4)/(1 + 3) = -3/4
The 6th term T₆ = 6(6 - 4)/(6 + 3) = 6(2)/9 = 2(2)/3 = 4/3
So, the sum of the 1st and 6th terms is T₁ + T₆ = -3/4 + 4/3
= (-9 + 16)/12
= 7/12
The answer is d.subx=0/y=0
Three is also 44 and two and four are 136
First, we need to solve for the common ratio from the data given by using the equation.
a(n) = a(1) r^(n-1)
15 = -3 r^(2-1)
-5 = r
r = -5
Then, we can find the sum by the expression:
S(n) = a(1) ( 1 - r^n) / 1-r
S(8) = -3 (1 + 5^8) / 1+5
S(8) = -195313
