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3 years ago

6

What is the mean of this data set? 12,17,16,10,20,13,14,14,12,12,19,18

2 answers:

OLga [1]3 years ago

8 0

Hello There!

Mean: Average of numbers in a set of data.

STEP 1: Add the numbers up. In this case, we would add

12 + 17 + 16 + 10 + 20 + 13 + 14 + 14 + 12 + 12 + 19 + 18 = 177

STEP 2: Divide the sum of the number by the number of digits you added.

We would divide 177 "sum of numbers" by 12 "number of digits" and would

get a quotient of 14.75

<u><em>The mean for this set of data is 14.75</em></u>

<u><em></em></u>

Gemiola [76]3 years ago

7 0

Answer:

14.75 :) please give me brainliest :)

Step-by-step explanation:

You might be interested in

What is a mixed number equivalent to 3.750

Anastasy [175]

The answer to your question is 3 3/4.. i hope its right.

6 0

3 years ago

Quadrilateral PQRS is circumscribed about a circle. Line PQ is tangent to the circle at A, line QR at B, line RS at C, and line

yuradex [85]

The sum of the angles of a quadrilateral is 360 degrees. So P+Q+R is 206, 360 - 206 = 154 degrees, the measure of angle S.

The four triangles, AQB, BRC, CSD, and DPA are all isosceles. So angle QBA = angle BAQ, etc. We find QBA = (180-24)/2 or 78 degrees.

RBC = (180-114)/2 = 33 degrees.

180 - (78 + 33) is the measure of angle B: 69 degrees.

The student should be able to see how to calculate the missing information from this.

6 0

2 years ago

Last year, nine employees of an electronics company retired. Their ages at retirement are listed below.

GuDViN [60]

Answer:

58.0

Step-by-step explanation:

Given the data:

56 65 62 53 68 58 65 52 56

Reorderd data: 52, 53, 56, 56, 58, 62, 65, 65, 68

Median = 1/2(n + 1) th term

n = sample size = 9

Hence,

Median = 1/2(9 + 1)th term

Median = 1/2(10)th term

Median = 5th term

5th term in the reordered data = 58

Hence, median age is 58

7 0

3 years ago

A line has a slope of -5/3. Through which two points could this line pass?

ladessa [460]

If there is no other context, you could use the points (0,0) and (3,-5) because you move down 5 and to the right 3.

3 0

3 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

3 years ago