All categories

3 years ago

A line has a slope of -5/3. Through which two points could this line pass?

Mathematics

1 answer:

ladessa [460]3 years ago

3 0

If there is no other context, you could use the points (0,0) and (3,-5) because you move down 5 and to the right 3.

You might be interested in

Solve 3(x - 2) < 18.

Anni [7]

- {x | x < 8}

- Divide each term by 3 and simplify.

- x - 2 < 6

- Move all terms not containing x to the right side of the inequality.

3 0

3 years ago

What is the sum of the series? 4 ∑k=1 (2k^2−4)

larisa86 [58]

The sum of the series $\sum_{k=1}^{4}\left(2 k^{2}-4\right)$ is 44.

Step-by-step explanation:

The given series is $\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

To find the sum of the series, we need to substitute the values for k in the series.

$\sum_{k=1}^{4}\left(2 k^{2}-4\right)=\left[2(1)^{2}-4\right]+\left[2(2)^{2}-4\right]+\left[2(3)^{2}-4\right]+\left[2(4)^{2}-4\right]$

Now, simplifying the square terms, we get,

$[2(1)-4]+[2(4)-4]+[2(9)-4]+[2(16)-4]$

Multiplying the terms,

$[2-4]+[8-4]+[18-4]+[32-4]$

Subtracting the values within the bracket term, we get,

$-2+4+14+28$

Now, adding all the terms, we get the sum of the series,

$\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

Thus, the sum of the series is $\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

8 0

3 years ago

PLEASE HELP I NEED TO TURN THIS IN FAST

olga2289 [7]

Answer:

you can do ittt

Step-by-step explanation:

i know you can

3 0

2 years ago

Read 2 more answers

What is the area of a square that measures 3.1 m on each side?

jasenka [17]

Answer:

The area of a square is S^2 where S is the length of the side.

Area = 3.1^2 = 3.1 x 3.1 = 9.61 m^2

8 0

3 years ago

Find the volume of the right prism.<br> For number 4

kvasek [131]

The answer is 36
Answer - 36

7 0

3 years ago

Read 2 more answers