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ivolga24 [154]
4 years ago
5

PLEASE HELPPP!!!!!! Write an equation of the line passing through point P that is perpendicular to the given line.

Mathematics
1 answer:
ArbitrLikvidat [17]4 years ago
4 0

Answer:(d): y=ax+b (a≠0); (d1)y=-4x+13

because of (d)⊥(d1) --> a.(-4)=-1 --> a=\frac{1}{4}

(d): y=\frac{1}{4}x+b. (d) pass through  P(-1;-2) so we have

-2=(1/4).(-1)+b ---> b=\frac{-7}{4}

(d) y= \frac{1}{4}x+ \frac{-7}{4}

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PLEASE HELP! I will award brainliest to the most helpful answer. I need an in depth explanation, not just the answer. How do you
Svetradugi [14.3K]

Answer:

y ≤ -4x+25

Step-by-step explanation:

First we need to figure out the equation for the line

The y intercept is  25

Next figure out the slope

slope = (y2-y1)/((x2-x1)

      = (49-25)/(-6-0)

      = 24/-6

    = -4

The equation for a line in slope intercept form is y = mx+b

y = -4x+25

This is a solid line so our inequality will have an equals in it.

It is shaded below, so y is less than.

If it was shaded above, y would be greater than

y ≤ -4x+25

8 0
3 years ago
don't pay attention to my work right there because I'm not sure if it's right, the correct answer is c because the teacher say i
TEA [102]
Exponential in form. y=AB^x
put data into calc should get
A = 1000 and B = 1.06
y=1000(1.06^x)

x=30 years, y=1000(1.06^30)=5743

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5 0
3 years ago
M=⅗ and y intercept is -6
ladessa [460]

Answer:

y=\frac{3}{5}x-6

Step-by-step explanation:

Remember the slope-intercerpt form

y=mx+b

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3 years ago
Can you please help. I will give brainleast. Oh and please have an explanation.
Ugo [173]
25/36

Cause I’m smort
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2 years ago
Read 2 more answers
Model With Mathematics A photographer is
Damm [24]

Answer:

a. The possible dimensions of the total area are;

The width of the total area is (2·x + 8) inches

The length of the total area is (2·x + 10) inches

b. The dimensions of the photos are as follows;

The length of the photos are 10 inches

The width of the photos are 8 inches

Step-by-step explanation:

a. Given that the area, A = 4·x² + 36·x + 80

We get;

A = 4 × (x² + 9·x + 20) = 4 × (x + 4) × (x + 5) = (2·x + 8)·(2·x + 10)

Therefore, the possible dimensions of the total area (photo + mat) are;

The width of the total area (photo + mat) = (2·x + 8) in.

The length of the total area (photo + mat) = (2·x + 10) in.

b. The dimensions of the photos alone are shorter than the dimensions of the photo and mat combined by 2·x each

Therefore, we have the dimensions of the photos are as follows;

The length of the photo = (2·x + 10) in. - 2·x in. = 10 in.

The width of the photos = (2·x + 8) in. - 2·x in. = 8 in.

3 0
3 years ago
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