Answer:
(- 7, - 4 )
Step-by-step explanation:
Given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the turning point is
x = - 
y = x² + 14x + 45 ← is in standard form
with a = 1, b = 14 , then
x = - 
= - 7
Substitute x = - 7 into the equation and evaluate for y
y = (- 7)² + 14(- 7) + 45 = 49 - 98 + 45 = - 4
coordinates of turning point = (- 7, - 4 )
- 67
substitute the given values for x and y into the expression and evaluate
= - 6(2)³ - (4)² - 3 = ( - 6 × 8 ) - 16 - 3 = - 48 - 16 - 3 = - 67
I conclude that the sum will be even because any even number can be represented by 2n where n is a whole number
and even numbers are 2 apart, so
the sum of the first 15 are
2n+2(n+1)+2(n+2) etc until we get to 2(n+14)
we can undistribute the 2 from all of them and get
2(n+n+1+n+2...n+14)
and we are sure that whatever is in the parenthasees is a whole number because whole+whole=whole
therefor, the sum is even
if you did want to find the sum then
an=2n
the 15th even number is 30
the first is 2
S15=15(2+30)/2=15(32)/2=15(16)=240
which is even
