All categories

4 years ago

Compare the size of Earth with that of the Sun, the solar system, and a galaxy.

Physics

2 answers:

hram777 [196]4 years ago

8 0

Answer:

Galaxy > The solar system > The sun > The earth

Explanation:

A galaxy is usually defined as a large accumulation of interstellar dust and gas particles, and also includes many solar systems, the sun, the planets, and other rocky planets. The name of the galaxy comprising the earth and the sun is the Milky way galaxy. The milky way galaxy has a diameter ranging between 150,000 and 200,000 light-years.

The solar system is composed of the nine planets including the asteroid belt, that goes around the sun in different orbits. The size of the Solar System is about 287.46 billion km in terms of diameter.

The sun is located at the central portion of the solar system that is the main source of energy. Its size is roughly 695,510 km in terms of diameter.

The earth is the only planet where life exists and is the 3rd planet that is closer to the sun, having a diameter of approximately 12,742 km.

saveliy_v [14]4 years ago

7 0

Answer:

Explanation:

Sun is about 109 times the diameter of the earth. It means that the radius of the sun is about:

$R_s=109\times 64000$

$R_s=6976000\ km$

Earth is about the size of an average sun-spot.

Our solar system is about 36 billions times huge than the size of the earth. The total mass of the solar system is about 333,345.997 times the mass of the Earth.
Earth contributes only about 0.2 % of the total mass of all the planets of our solar system.

Our galaxy is milky way and our solar system orbits around the galactic center at a radial distance of about 28000 light-years.

The time period of this revolution is approximately 250 million years.

According to a scientific data there could be as many as 40 billion Earth-sized planets orbiting in the habitable zones of sun-like stars and red dwarf stars within the Milky Way Galaxy.

You might be interested in

Where is the turning effect of a force greater on a door

Varvara68 [4.7K]

Answer:

Explanation: forces can cause an object to rotate and the turning effect of the force is called a moment. If a resultant force acts on an object about a fixed turning point it will cause the object to rotate e.g. turning a with a spanner, applying a screwdriver, opening a door fixed on

3 0

3 years ago

If you place small pieces of tissue paper near the balloon in Picture 2, they would probably stick to the

pishuonlain [190]

Answer:

The balloon has more negative charges than positive charges. The tissue paper has a neutral charge.The static electricity pulls on the tissue paper lifting it up.

4 0

3 years ago

A 7.0 mm -diameter copper ball is charged to 40 nC. What fraction of its electrons have been removed? The density of copper is 8

mylen [45]

Answer:

$f = 2.6 \times 10^{-13}$

Explanation:

Let the mass of copper ball is "m" gram

now the total number of copper atom present in the ball is given as

$N = \frac{m}{29} \times 6.02 \times 10^{23}$

now the total number of electrons in one copper atom is 29

so total number of electrons in given sample of copper ball is

$N_e = m(6.02 \times 10^{29})$

now diameter of the ball is 7.0 mm

density of the ball = $8900 kg/m^3$

now we have

$m = (\frac{4}{3}\pi r^3)(8900)$

$m = (\frac{4}{3}\pi(\frac{0.007}{2})^3)(8900)$

$m = 1.6 gram$

now we have

$N_e = 9.63 \times 10^{23}$

now the charge on the copper ball is 40 nC

so the number of electrons removed

$Q = ne$

$40 \times 10^{-9} = n(1.6 \times 10^{-19}$

$n = 2.5 \times 10^{11}$

so the fraction of number of electrons removed is given as

$f = \frac{n}{N_e}$

$f = \frac{2.5 \times 10^{11}}{9.63 \times 10^{23}}$

$f = 2.6 \times 10^{-13}$

7 0

4 years ago

A 31 cm tall object is placed in front of a concave mirror with a radius of 34 cm. The distance of the object to the mirror is 9

Setler [38]

Focal length is the distance between the center of a convex lens or a concave mirror and the focal point of the lens or mirror — the point where parallel rays of light meet, or converge. From the optics the focal length of the mirror can be defined as the radius of the mirror divided between two, or in other words, half the radius of the mirror.

$f = \frac{R}{2}$