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yarga [219]
3 years ago
12

At its closest point, Mercury is approximately 46 million kilometers from the sun. What is this distance in AU?

Physics
2 answers:
alina1380 [7]3 years ago
5 0
1 astronomical unit 1 AU = 1.4960 * 10^11 meters
it is the average distance between earth and sun
mercury to sun distance is = 46,000,000 * 1000 meters
               = 4.6 * 10^9 meters = 4.6 * 10^9 / 1.4960 * 10^11  AU
               =  3.0.74 / 100  = 0.0374 AU

Radda [10]3 years ago
5 0

Explanation :

Astronomical unit is the unit to find the average distance between the earth and the sun.

1\ AU=1.496\times 10^8\ Km

So, 1\ Km=\dfrac{1}{1.496\times 10^8}\ AU

46 million kilometers means, 46\times 10^6\ Km

46\times 10^6\ Km=\dfrac{46\times 10^6}{1.496\times 10^8}

46\ million\ Km=0.3074\ AU

Hence, this is the required solution.      

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A speedboat moving at 29.0 m/s approaches a no-wake buoy marker 100 m ahead. The pilot slows the boat with a constant accelerati
Goshia [24]

Answer:

t =4.8sec

Explanation:

From the question we are told that

Velocity of speed boat V=29.0m/s

Distance to Marker d=100

Acceleration of a=-3.4m/s^2

Generally the Newtons 3rd motion equation is given as

 v^2 = u^2 + 2 * a* s

 v^2 = 29^2 + 2 * -3.4* 100

 v = \sqrt{161}

 v=12.68m/s

Generally the Newton's first equation of motion is given as

 v = u + a*t

 12.68 = 29 -3.4*t

 12.68-29 =  -3.4t

 -16.32 =  -3.4t

 t =\frac{-16.32}{-3.4}

 t =4.8sec .

8 0
3 years ago
In a machining operation that approximates orthogonal cutting, the cutting tool has a rake angle =100 . The chip thickness ratio
Rudik [331]

Answer:

The percentage of the total energy dissipated into shear plane is 89.46%.

Explanation:

Given that,

Rake angle = 10°

Thickness ratio= 0.5

Cutting Force = 400 N

Thrust force = 200 N

Speed =3 m/s

Suppose the shear force is 345.21 N.

We need to calculate the shear plane angle

Using formula shear angle

\tan\phi=\dfrac{r\cos\alpha}{1-r\sin\alpha}

Put the value in to the formula

\tan\phi=\dfrac{0.5\cos10}{1-0.5\sin10}

\tan\phi=0.539

\phi=\tan^{-1}(0.539)

\phi=28.32^{\circ}

We need to calculate the shear velocity

Using formula of shear velocity

v_{2}=\dfrac{v\cos\alpha}{\cos(\phi-\alpha)}

Put the value into the formula

v_{2}=\dfrac{3\times\cos10}{\cos(28.32-10)}

v_{2}=3.11\ m/s

We need to calculate the percentage of the total energy dissipated into shear plane

Using formula of energy dissipated

\%d=\dfrac{P_{s}}{P}\times100

\%d=\dfrac{F_{s}\times v_{c}}{F_{c}\times v}\times100

Put the value into the formula

\%d=\dfrac{345.21\times3.11}{400\times3}\times100

d=89.46\%

Hence, The percentage of the total energy dissipated into shear plane is 89.46%.

6 0
3 years ago
If one wave of 10 m amplitude meets constructively with another of amplitude 20
steposvetlana [31]

Answer:

B. 30m

Explanation:

This is because when a wave interferes constructively with another wave, they will add since constructive relates to joining or building up.

So, 10m + 20m equals a 30m wave.

3 0
4 years ago
Sirius and its companion orbit around a common center of mass with a period of 50 years. The mass of Sirius is 2.35 times the ma
s2008m [1.1K]

Answer:

1 solar masses

Explanation:

-Sirius has to maintain equilibrium with it's companion.

-Let x be the mass of Sirius and y be the mass of it's companion.

-From the question, we know that Sirius is 2.35 times heavier than it's companion:

\frac{x}{y}=2.35\\\\\frac{x}{y}=\frac{2.35}{1}

Hence, the mass of it's companion is 1 solar masses

3 0
3 years ago
An atom of 6/2 He decays by beta decay. What atom is left after decay
olya-2409 [2.1K]

Answer:

6/3 LI

Explanation:

7 0
3 years ago
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