Answer:
T= 1 s
Explanation:
Given that
When x= cm ,T= 1
we know that time period of spring mas system given as

T= Time period
m= mass
k=spring constant
So from above equation we can say that time period of system does not depends on the value of x.
So when x= 10 cm ,still time period will be 1 s.
T= 1 s
Explanation:
90 kmhr—1 x 1000/3600 = 25ms—1
U = 0 ms—1
V = 25ms—1
t = 10 s
a = ?
a = V - U/t
a = 25 - 0/10
a = 25/10
a = 2.5 ms—1
Unless if all forces cancel each other out , the object will no longer be in equilibrium
Answer:
K = 588.3 N/m
Explanation:
From a forces diagram, and knowing that for the maximum value of K, the crate will try to rebound back up (Friction force will point downward):
Fe - Ff - W*sin(22) = 0 Replacing Fe = K*X and then solving for X:

By conservation of energy:

Replacing our previous value for X and solving the equation for K, we get maximum value to prevent the crate from rebound:
K = 588.3 N/m