Answer:
a)
b) For this case we se that
Since the power is constant but the frequency is doubled we will see that
So the original amplitude is
And if the frequency is doubled we have that:
So then we will see that the amplitude would be reduced the half and for this case:
Explanation:
For this case we have the following data given:
represent the diameter
represent the radius
represent the tension
represent the frequency of the oscillator
represent the amplitude of the wave
Part a
For this case we can assume that the power transmitted to the wave is the same power of the oscillator. and we have the following formula for the power:
This expression can be written in different ways:
Where f is the frequency , T the tension the density of the steel, A the amplitude and the area, so then we have everuthing in order to replace and we got:
Part b
For this case we se that
Since the power is constant but the frequency is doubled we will see that
So the original amplitude is
And if the frequency is doubled we have that:
So then we will see that the amplitude would be reduced the half and for this case: