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natima [27]
3 years ago
5

The mass of a sample of sodium bicarbonate is 2. 1 kilograms (kg). There are 1,000 grams (g) in 1 kg, and 1 Times. 109 nanograms

(ng) in 1 g. What is the mass of this sample in ng? 2. 1 Times. 103 ng 2. 1 Times. 106 ng 2. 1 Times. 109 ng 2. 1 Times. 1012 ng.
Physics
1 answer:
slega [8]3 years ago
3 0

2.1 kg of sodium bicarbonate is equal to the 2.1 x 10¹² ng of sample. Option D is correct.

Mass is the quantity of the substance in the body or object. The SI unit of mass is Kilogram.

There are other units of measure,

  • Milligram: 1 g is equal to the \bold {10^3 \ mg}
  • Micro-gram: 1 g is equal to \bold {10^{6} \ \mu g}
  • Nano-gram: 1 g is  is equal to\bold {10^{9} \ ng}

First convert kg to gram,

Since, 1 Kg = 1000 g

2.1 kg = grams of sample

So,

Do the cross multiplication,

\rm mass\ of\ sample = \dfrac {2.1\ kg \times  1000\ g }{ 1 kg}\\\\\rm mass\ of\ sample =2100 g

Now, convert 2100 g to nano-grams

Since, 1 g = 1 x 10⁹ ng

2100 g = ng of sample

So,

Do the cross multiplication,

\rm mass\ of\ sample  = \dfrac {2100 g \times  1 \times  10^9 ng }{1\ g}\\\\\rm mass\ of\ sample  = 2.1 \times 10^1^2 ng

Therefore, 2.1 kg of  sodium bicarbonate is equal to the 2.1 x 10¹² ng of sample.

To know more about Mass units,

brainly.com/question/489186

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Alex Ar [27]

Answer:

They have same density

Explanation:

The density of an object is defined as

d=\frac{m}{V}

where

m is the mass of the object

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Let's call m_c and V_c the mass and the volume of ball C, respectively. Therefore, the density of ball C is:

d_c = \frac{m_c}{V_c}

We know that the volume of ball C is 3 times the volume of ball D, so

V_c = 3 V_d \rightarrow V_d = \frac{V_c}{3}

And we also know that ball D has 1/3 the mass of ball C:

m_d = \frac{m_c}{3}

So, the density of ball D is:

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Therefore, the two balls have same density.

6 0
4 years ago
A spacecraft has a momentum of 20,000 kg-m/s, and a mass of 250 kg. What is the magnitude of its velocity?
Harlamova29_29 [7]

Answer:

<h2>A. 80 m/s </h2>

Explanation:

The velocity of the spacecraft can be found by using the formula

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From the question we have

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We have the final answer as

<h3>80 m/s</h3>

Hope this helps you

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3 years ago
A 910-kg object is released from rest at an altitude of 1200 km above the north pole of the Earth. If we ignore atmospheric fric
gayaneshka [121]

In order to develop this problem it is necessary to use the concepts related to the conservation of both potential cinematic as gravitational energy,

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m = Mass of Object

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v^2 =  -2GM(\frac{1}{r_1}-\frac{1}{r_2})

v^2 = -2*(6.673 *10^-11)(5.98 *10^24) (\frac{1}{(7.571 *10^6)} -\frac{1}{(6.371 *10^6)})

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Answer:

s = 45 m

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The velocity given in the question is uniform. Hence, the formula for the uniform velocity shall be used here. The formula is given as follows:

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RoseWind [281]

GOOD MORNING HAVE A NICE DAY

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