Answer:
The exact answer in terms of radicals is ![x = 5*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%205%2A%5Csqrt%5B3%5D%7B25%7D)
The approximate answer is 
(accurate to 5 decimal places)
===============================================
Work Shown:
Let ![y = \sqrt[5]{x^3}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B5%5D%7Bx%5E3%7D)
So the equation reduces to -7 = 8-3y
Let's solve for y
-7 = 8-3y
8-3y = -7
-3y = -7-8 ... subtract 8 from both sides
-3y = -15
y = -15/(-3) ... divide both sides by -3
y = 5
-----------
Since and y = 5, this means we can equate the two expressions and solve for x
![\sqrt[5]{x^3} = 5](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E3%7D%20%3D%205)
Raise both sides to the 5th power
![x = \sqrt[3]{3125}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B3125%7D)
Apply cube root to both sides
![x = \sqrt[3]{125*25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B125%2A25%7D)
![x = \sqrt[3]{125}*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B125%7D%2A%5Csqrt%5B3%5D%7B25%7D)
![x = \sqrt[3]{5^3}*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B5%5E3%7D%2A%5Csqrt%5B3%5D%7B25%7D)
Answer:
Step-by-step explanation:
Six times a number is decreased by fourteen, the result is 124.
Write an equation that represents this
(6 * x) - 14 = 124
Multiply 6 by x to remove the parenthesis
6x - 14 = 124
Add 14 to both sides of the equation
6x = 138
Divide both sides of the equation by 6
x = 23
The unknown number is
Hope this helps :)
I think it would a minimum because its positive. and the vertex would be (-.77,4.55) the minimum is 4.55
Step-by-step explanation:
20a + 158+6c=you will expand the brackets
= so it is 120+60+48
20a+158+6c=120+60+48
20a+ 6c=120+60+48-158
20a+6c=70
20a divide by 20+6c divide by 6 on both side
a + c = 0.58
Answer:
-55
Step-by-step explanation:
