Answer:
Here's a possible example:
Step-by-step explanation:

Each piece is linear, so the pieces are continuous by themselves.
We need consider only the point at which the pieces meet (x = 3).

The left-hand limit does not equal ƒ(x), so there is a jump discontinuity at x =3.
450/313*10.5 = 15.09.... which is approx is 15
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