Answer:
a-bi
Step-by-step explanation:
If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi
Because we have l, m and n are real numbers and they are the coefficients.
Sum of roots = a+bi + second root = -m/l
When -m/l is real because the ratio of two real numbers, left side also has to be real.
Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.
i.e. other root will be of the form c-bi for some real c.
Now product of roots = (a+bi)(c-bi) = n/l
Since right side is real, left side also must be real.
i.e.imaginary part =0
bi(a-c) =0
Or a =c
i.e. other root c-bi = a-bi
Hence proved.
Answer:
The solution is 
Step-by-step explanation:
The equation
can be rewritten as
and can be further simplified to
.
Now, taking the inverse sine of both sides we get:
The value of the right side on the interval 
is
,
which makes the equation (2)
solving for 
gives
which is our solution.
Answer:
the answer is B
Step-by-step explanation:
Each mark represents 20%, you move right three times. 20x3 = 60
60%
