What is the context for the question if there is any?
I think around 44% chance that all three flights would arrive on time, but i'm not that sure.
First, you plot the coordinates to visualize the problem clearly. As you can see in the picture, the longest sides could either be one of those marked in red. This could be initially determined when you use visual estimation. We measure this using the distance formula: d = √[(x2-x1)^2 + (y2-y1)^2)]
Between coordinates (0,3) and (3,6)
d = √[(3-0)^2 + (6-3)^2)]
d= 4.24 units
Between coordinates (2,1) and (5,4)
d = √[(5-2)^2 + (4-1)^2)]
d= 4.24 units
They are of equal length. Both are the longest sides which measures
4.24 units.
In order to solve the equation, set up a proportion. Use the similar sides together!
1. 16/8 = x/20.... Similar sides are in one ratio and they equal another ratio...."x" represents the side of VS
2.Solve for "x" by cross multiplying: 8x = 320
3. Divide by 8 to find "x": x = 40
Side VS equals 40. Hope this helped :)
Answer:
<h2>18%</h2>
Step-by-step explanation:
Step one;
given
initial weight = 55 pounds
final weight= 45 pounds
Step two:
Required
the % weight decrease
% decrease= initial-final/initial *100
% decrease= 55-45/55 *100
% decrease= 10/55 *100
% decrease= 0.18 *100
% decrease= 18%