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SashulF [63]
3 years ago
5

Please help me solve them

Mathematics
2 answers:
deff fn [24]3 years ago
8 0
Ok so the first thing to do would be get rid of the fraction. To do that multiply the ENTIRE equation but the denominator. Once all the numbers are multiplyed I think it’ll be easier for u to solve them :) or if u wanna solve them quick, download Photomath :)
gavmur [86]3 years ago
6 0
1) x= 22

2) x= -2

3) x= -5

4) x= 7
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I need help here too
8090 [49]

Answer:

1. B    2. D    3. C    4. B

8 0
2 years ago
Someone please help me with 16-18 please it’s due in 30 mins
AlekseyPX

9514 1404 393

Answer:

  16.  134°

  17.  20°

  18.  94°

Step-by-step explanation:

An inscribed angle is half the measure of the arc it intercepts.

__

16. Arc QT is twice the measure of inscribed angle QST, given as 67°.

  Arc QT = 2×67°

  Arc QT = 134°

__

17. Angle STR is half the measure of arc SR, so is ...

  m∠STR = (arc SR)/2 = 40°/2

  m∠STR = 20°

__

18.  Arc RST is a semicircle, so has a measure of 180°. Then arc ST is the difference between that and arc RS:

  arc ST = 180° -40° = 140°

Angle RST subtends a semicircle, so is 180°/2 = 90°. We know angle QST is 67°, so the remaining portion, angle QSR must be the complement of that:

  m∠QSR = 90° -67° = 23°

Arc RQ will be twice this measure, or 46°.

So, the desired difference is ...

  mST -mRQ = 140° -46° = 94°

3 0
3 years ago
PLZ HURRYY!!<br>Solve for p.<br><br>5p – 7 &gt; – 12
Anarel [89]

I am gonna do what you did to me and say its easy.

8 0
3 years ago
Jada is watching a movie for a history report. she has 1 over 4, of the movie left to watch. jada plans to watch the remainder o
koban [17]
She would watch like 3 in a half
4 0
4 years ago
What is the radius of a sphere with a volume of 1/6 pie
Yakvenalex [24]

Answer:

\large\boxed{the\ radius\ R=\dfrac{1}{2}}

Step-by-step explanation:

The formula of a volume of a sphere:

V=\dfrac{4}{3}\pi R^3

We have

V=\dfrac{1}{6}\pi

Substitute:

\dfrac{4}{3}\pi R^3=\dfrac{1}{6}\pi        <em>divide both sides by π</em>

\dfrac{4}{3}R^3=\dfrac{1}{6}          <em>multiply both sides by 3</em>

3\!\!\!\!\diagup^1\cdot\dfrac{4}{3\!\!\!\!\diagup_1}R^3=3\!\!\!\!\diagup^1\cdot\dfrac{1}{6\!\!\!\!\diagup_2}

4R^3=\dfrac{1}{2}          <em>divide both sides by 4</em>

R^3=\dfrac{1}{2}:4\\\\R^3=\dfrac{1}{2}\cdot\dfrac{1}{4}\\\\R^3=\dfrac{1}{8}\to R=\sqrt[3]{\dfrac{1}{8}}\\\\R=\dfrac{\sqrt1}{\sqrt8}\\\\R=\dfrac{1}{2}

3 0
3 years ago
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