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SashulF [63]
3 years ago
5

Please help me solve them

Mathematics
2 answers:
deff fn [24]3 years ago
8 0
Ok so the first thing to do would be get rid of the fraction. To do that multiply the ENTIRE equation but the denominator. Once all the numbers are multiplyed I think it’ll be easier for u to solve them :) or if u wanna solve them quick, download Photomath :)
gavmur [86]3 years ago
6 0
1) x= 22

2) x= -2

3) x= -5

4) x= 7
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Given the figure below, find the values of x and z.
aleksandrvk [35]

Answer: x = 2 and z=78

Step-by-step explanation:

Opposite angles are non-adjacent angles formed by two intersecting lines. Opposite angles are congruent (equal in measure). Z is Opposite to 78 angle, so z=78.

Adjacent angles add up to 180 degrees, and 78 and (5x + 92) are adyacents so:

5x + 92 + 78 = 180

5x + 170 = 180

5x = 180 - 170

5x = 10

x = 10/5

x = 2

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3 years ago
Can anyone help me with this problem?
Mrac [35]

Answer: The number of tomatoes went up relative to the increase of fertilizer used. the slope is positive.

Step-by-step explanation:

6 0
4 years ago
Please help will mark the brainliest
trasher [3.6K]

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She has $10 left.

Step-by-step explanation:

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3 years ago
Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7  y coordinate=-2

B: x coordinate=1  y coordinate=-2

C: x coordinate=1  y coordinate=-8

D: x coordinate=-7  y coordinate=-8

G: x coordinate=2  y coordinate=5

H: x coordinate=6  y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis  with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>

<em />

Points J and K could be located at:

J(2,2)

K(6,2)

3 0
3 years ago
Can someone plz help this is like my 5th time putting up this question!!!
serg [7]

Answer:

the table should be 25,98,173,248

3 0
3 years ago
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