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jolli1 [7]
3 years ago
11

25 POINTS

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0
[ 1 ] Given
[ 2 ] Exterior Sides Opposite Rays
[ 3 ] Definition of Supplementary angles
[ 4 ] First substitution
[ 5 ] Subtraction Property of Equality
[ 6 ] Second Substitution
[ 7 ] If corrsp. equal, the lines ||
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I need help with this I don't get it at all
iren [92.7K]

Answer:

the answer is C

Step-by-step explanation:

because the negative needs to be on the inside not on the outside

8 0
3 years ago
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Evaluate the following expression. [4 + (12 - 2) ÷ 5] ÷ 7
Anika [276]

Answer:

[4 + (12 - 2) ÷ 5] ÷ 7

[4 + 6 / 5] / 7

[10 / 5] / 7

2 / 7

= 2/7 or 0.28571428571

7 0
2 years ago
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Triangle KML and triangle PRQ are shown in the figure belowK404008 cms4 cms10 cmsOL3 cms6 cmsRM17) Are these triangles similar?1
s2008m [1.1K]

Two triangles are similar if the only difference between them is the size, this means that their internal angles must be the same. If we look at the picture the first triangle has one angle equal to 40 degrees, one equal to 80 degrees and the third one is unkown (x). The second triangle has one angle equal to 40 degrees, one equal to 60 degrees and the third one is unkown (y). The sum of the internal angles of a triangle must be equal to 180 degrees, with this information we can find the values of the missing angles. We have:

\begin{gathered} 40+80+x=180 \\ 120+x\text{ = 180} \\ x\text{ = 180-120=60} \end{gathered}\begin{gathered} 40+60+y=180 \\ 100+y=180 \\ y=180-100=80 \end{gathered}

Therefore the internal angles of the first triangle are (40,80,60) and the angles of the second triangle are (40,80,60) as well, therefore they are similar.

Two triangles are congruent if they have sides with the same length. Which is not the case, because the sides of one triangle is (8, 10, 6) while the other is (4,3 and unkown). Therefore they are not congruent.

8 0
1 year ago
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min. The volume of a sphere is V = 4 3 πr3 and its surface
Scrat [10]

Answer:

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

Step-by-step explanation:

The area of a sphere is given by the following formula:

A = 4\pi r^{2}

In which A is the area, measured in cm², and r is the radius, measured in cm.

Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.

This means that \frac{dr}{dt} = 40

Determine the rate of change in surface area when r = 20 cm.

This is \frac{dA}{dt} when r = 20. So

A = 4\pi r^{2}

Applying implicit differentiation.

We have two variables, A and r, so:

\frac{dA}{dt} = 8r\pi \frac{dr}{dt}

\frac{dA}{dt} = 8*20\pi*40

\frac{dA}{dt} = 20106.19

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

6 0
3 years ago
A painter is painting a mural on a wall. He has a 25-foot ladder. He needs to work on a part of the wall that is 24 feet above t
ICE Princess25 [194]

Answer: 7 feet

Step-by-step explanation:

4 0
3 years ago
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