The 2 smallest lengths in a triangle have to add up to be greater that the longest side of the triangle. In this case, the longest side is 20. The 2 smallest sides are 5 and 10. 5+10=15, but 15<20. This is why these 3 lengths can’t create a triangle.
Answer:
D) cannot factor
Step-by-step explanation:
D) cannot factor
Answer:
The graph of this piece-wise function is attached below.
Step-by-step explanation:
Given the function
- A piece-wise function is a function which has multiple pieces.
- Each of the pieces have their own restrictions.
- The domain of a function is the set of input, or x, values for which the function is defined.
- The range is the set of all values taken by the function
As the piece
has the domain [-5, 3) and graph of this piece is attached below.
and
has the domain [3, 7) and graph of this piece is attached below.
So, the domain of the piece-wise function can be composed as [-5, 3) U [3, 7) and range has the interval
.
i.e.
Domain: [-5, 3) U [3, 7)
Range: ![\:\left[-1,\:27\right]](https://tex.z-dn.net/?f=%5C%3A%5Cleft%5B-1%2C%5C%3A27%5Cright%5D)
The graph of this piece-wise function is attached below.
<em>Keywords: piece-wise function, domain, range</em>
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Answer:
For f(x) = 2x + 3 and g(x) = -x 2 + 1, find the composite function defined by (f o g)(x)
(f o g)(x) = f(g(x))
= 2 (g(x)) + 3
= 2( -x 2 + 1 ) + 3
= - 2 x 2 + 5 Given f(2) = 3, g(3) = 2, f(3) = 4 and g(2) = 5, evaluate (f o g)(3)
Step-by-step explanation:
Answer:
Step-by-step explanation:
By applying tangent rule in the given right triangle AOB,
tan(30°) = 


By applying tangent rule in the given right triangle BOC,
tan(60°) = 
OC = BO(√3)
OA + OC = AC

2√3(BO) = 60
BO = 10√3
OC = BO(√3)
OC = (10√3)(√3)
OC = 30
By applying tangent rule in right triangle DOC,
tan(60°) = 
OD = OC(√3)
OD = 30√3
Since, BD = BO + OD
BD = 10√3 + 30√3
BD = 40√3
≈ 69.3