<span>The equation is not quadratic in for because it cannot be written as a second degree polynomial</span>
Answer: 4.5
<u>Step-by-step explanation:</u>
First, find the points of intersection by solving the system.
y = x² + 2x + 4
y = x + 6
Solve by substitution:
x² + 2x + 4 = x + 6 ⇒ x² + x - 2 = 0 ⇒ (x + 2)(x - 1) = 0 ⇒ x = -2, x = 1
Now, integrate from x = -2 to x = 1
<em>the bottom of the integral is -2 </em>
= 
= 
= 
= 
= 
= 
= -3 + 1.5 + 6
= 4.5
If they're integers, that means they can't be fractions (such as 15/2 and 2).
So the only couples of integers that, when multiplied, result in 15 are:
1 and 15
5 and 3.
(there are no other possibilities as both 5 and 3 are not divisible further).
The smaller of the two sums (15+1; 5+3) is 5+3=8.
The least possible sum of a and b is 8.
Answer:
Y = 5x -4
Step-by-step explanation:
You literally just plug the numbers into the equation below:
y = mx + b.
Answer:
Utiliza una cifra que pueda ser resultado de dividir 100:5 y eso a su vez nos dará el valor que debe aumentar en la escala
