1) c) y = 500 * 2^x
In year 1, x = 1 and the population is 500 * 2^1 = 1000
In year 2, this doubles to 500 * 2^2 = 500 * 4 = 2000
ans so on
This model describes the population doubling every year
2)
A) 3 (1/2)^x and C) (0.25)^x
These numbers reduce as x increases because there is a number with an absolute value less than 1 is being raised to the power of x. They also will never totally reach zero or become negative, but will approach zero as x becomes very large.
So,
5y*3 is the open phrase the student uses to model "the sum of 5y and 3".
"The sum of" means addition. The student put 5y*3, while the sum of 5y and 3 is actually 5y + 3.
Answer:
Yes
Step-by-step explanation:
Switch x for 6:
(6)-8=-2
Subtract 6 from 8:
-2=-2
-2 does equal -2 so 6 is a solution.
Answer:
D
Step-by-step explanation:
It's D on Edge, hope this helps
Answer:
3rd choice
Step-by-step explanation:
(7y^6)(2y^-4)^2
= (7y^6)(4y^-8)
Calculate:
(7y^6) * (4y^-8)
28y^-2
Express with a positive exponent:
28 * 1/y^2
