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3 years ago

Is -2,-2,-2 arithmetic geometric neither or both

Mathematics

1 answer:

gogolik [260]3 years ago

7 0

Answer: both

Step-by-step explanation:

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This last one I need help on too

ExtremeBDS [4]

Answer:

$x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}$

Step-by-step explanation:

simplify $\frac{-3}{x-2}$ by putting the negative sign on the outside. $\frac{2x}{x-1}-\frac{2x-5}{x^2-3x+2}=-\frac{3}{x-2}$

find the LCM of the denominators. It is (x-1)(x-2). Multiply by the LCM:

$\frac{2x}{x-1}\left(x-1\right)\left(x-2\right)-\frac{2x-5}{x^2-3x+2}\left(x-1\right)\left(x-2\right)=-\frac{3}{x-2}\left(x-1\right)\left(x-2\right)$

Simplify:

$2x\left(x-2\right)-\left(2x-5\right)=-3\left(x-1\right)$

solve: $x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}$

3 0

3 years ago

What happens to the value?

Fiesta28 [93]

Answer:

D.) c is multiplied by 4

Step-by-step explanation:

$c = \dfrac{8a^3}{b}$

If a is doubled, it becomes 2a. If b is doubled, it becomes 2b. Now we replace a with 2a and b with 2b and simplify.

$c = \dfrac{8(2a)^3}{2b}$

$c = \dfrac{8 \times 8a^3}{2b}$

$c = \dfrac{4 \times 8a^3}{b}$

$c = 4 \times \dfrac{8a^3}{b}$

Answer: D.) c is multiplied by 4

4 0

3 years ago

Find the exact value of sin 105º.

Jet001 [13]

Answer:

sin 105 = sin (45 + 60) = sin 45 cos 60 + cos 45 sin 60, or

= (1 / √2)(1 / 2) + (1 / √2)(√3 / 2)

1 + √3

= -------------

2√2

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If B is the midpoint of AC, AC=CD, AB=3x+4, AC=11x-17, and CE=49, find DE.

Luba_88 [7]

Answer:

Step-by-step explanation:

AB = 3x + 4 and AC which is twice of AB is equal to 11x - 17

2 (3x + 4) = 11x - 17

6x + 8 = 11x - 17

8 + 17 = 11x - 6x

25 = 5x

5 = x

AC = CD = 11x - 17 ➡ 11×5 - 17 = 38

CD = 38 and DE = 49 - 38 = 11

6 0

3 years ago

System of linear equations has been graphed in the diagram. Determine a reasonable solution for the system of equations.

umka2103 [35]

Answer:

D) (0, -3)

Step-by-step explanation:

The solution of two linear equations is the point of intersection of their graphs.

From the graph, the point of intersection of the graphs of the two linear equations is on the y-axis. So, the $x$ value on the $y$ axis is always 0. Also, the point is below the x-axis. So, the $y$ value of the point will be negative.

From the choices given, only (0,-3) matches the above conditions.

Therefore, the correct choice is D. (0, -3).

7 0

3 years ago