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Zepler [3.9K]
3 years ago
14

**10 POINTS! HELP ME OUT! YOU WILL BE HELPING ME TO BE HAPPY!**

Mathematics
1 answer:
Bond [772]3 years ago
4 0

Looking at the chart, we can see that with diet chow, the weight changed by -26, while with kitty diet, it changed by -13. Therefore, the Diet Chow was more effective

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The radius of a cylindrical vessel is 7 cm and height is 1400 m . Find the cost of painting its inner curved surface area at the
Olegator [25]

Answer:

Cost = 616000 DHS per square centimetre.

Step-by-step explanation:

curved surface of a cylinder = 2\pirh

r = 7 cm

h = 1400 m = 140000 cm

The outer curved surface area of the cylinder = inner curved surface area of the cylinder

The inner curved surface of the cylinder = 2\pirh

                                      = 2 x \frac{22}{7} x 7 x 140000

                                      = 2 x 22 x 1 x 140000

                                      = 6160000

The inner curved surface of the cylinder is 6160000 square centimetre.

But, the cost of painting is at the rate of 10 DHS per square centimetre.

The inner curved surface of the cylinder = 6.16 x 10^{6} square centimetre.

cost of painting the inner curved surface area = \frac{6.16*10^{6} }{10}

                                                                       = 616000 DHS per square centimetre

The cost of painting the inner surface is 616000 DHS per square centimetre.

6 0
3 years ago
Accrual income versus cash flow for a period. Thomas Book Sales, Inc., supplies textbooks to college and university bookstores.
agasfer [191]

This is Q.a

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3 years ago
Help Me Please!!!!1
Lena [83]

Answer:

The space inside the box = 2197 in³ - 1436.76 in³ is 760.245 in³.

Step-by-step explanation:

Here we have the volume of the cube box given by the following relation;

Volume of cube = Length. L × Breadth, B × Height, h

However, in a cube  Length. L =  Breadth, B = Height, h

Therefore, volume of cube = L×L×L = 13³ = 2197 in³

Volume of the basketball is given by the volume of a sphere as follows;

Volume = \frac{4}{3} \pi r^3

Where:

r = Radius = Diameter/2 = 14/2 = 7in

∴ Volume of the basketball = \frac{4}{3} \times  \pi \times 7^3 = 1436.76 \ in^3

Therefore, the space inside the box that is not taken up by the basketball is found by subtracting the volume of the basketball from the volume of the cube box, thus;

The space inside the box = 2197 in³ - 1436.76 in³ = 760.245 in³.

7 0
3 years ago
PLZ HELP AND HURRY, IM GIVING BRAINLIEST AND 50 POINTS!!! PLZ HURRY!!
IceJOKER [234]

Answer:

p yellow 11 over 15

Step-by-step explanation:

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3 years ago
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Solve the system of equations using substitution. y = x + 6 y = –2x – 3 (4, –11) (1, 7) (–3, 3)
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The answer to the question

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