Answer:
C. $142.50
Explanation:
From the existing contract,
200 units for $10 each
150 units were delivered so, 10 x 150= $1500.
The customer wants to extend the contract for additional 100 units at $9.50 each.
So,what is the revenue to Harold Corporation for these additional units which cost $9.50 for the next 15 units.
Therefore, 15 x 9.50= $142.504
The answers to the question are:
- The machine that is the constraint is the machine c.
- The product m = 80 units and n = 80 units
- Net profit = $3600
<h3>1. How to solve for the constraint of the machine</h3>
We have to solve for the workload of the machines
For A. 20*100 = 2000
For B, 5 * 100 + 10 *80
= 500 + 800 = 1300
For Machine C = 15 * 100 + 15 * 80
= 1500 + 1200
= 2700
The time at the workstation in c is more than the constant time of 2400, hence the constraint that we have is machine c.
b. 2400- 1200 = 1200
The product mix would be 1200/15
= 80
Hence the product mix m = 80 units and that of n = 80 units
<h3>c. The total net profit</h3>
80*$90 = 7200 , 80 * 105 = 8400
7200 + 8400
= 15600
The net profit = 15600 - 12000
= $3600
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Answer:
Trial Balance
Items Group Debit ($) Credit ($)
Cash Asset 37641
Office Supplies Asset 890
Prepaid Insurance Asset 4600
Office Equipment Asset 12900
Accounts Payable Liability 12900
Capital Equity 18000
Withdrawals Equity 3329
Engineering Fees earned Revenue 36000
Rent Expense Expense <u>7540</u> <u> </u>
Total <u>$66900</u> <u>$66900</u>
