Speed (S) = Distance (D) / time (t)
First stretch
45 = D / 2
D = 45*2
D = 90 mp
How is the same distance:
Second stretch
S = 90 / t
Average speed (AS):
AS = (S1+S2) / 2
60 = [45+(90/t)] / 2
120 = 45+90/t
120-45 = 90/t
75 = 90/t
t = 90/75
t = 1,2 h
________________________
And now:
S = 90 / t
S = 90 / 1,2
S = 75 mph
The answer to the addition problem 15 + 37 = 52
Answer:
Below.
Step-by-step explanation:
x^6 . x . x^3
= x^6 . x^1 . x^3
= x^(6+1+3)
= x^10.
