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seropon [69]
3 years ago
14

Study the table below.

Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0
Study the table below.

Day Stock Price
June 1st $40
September 1st $56
December 31st $47
Johan buys Quality Value Inc. stock at $45 a share on January 1st. On which date could he sell the stock for a capital gain?
A.
September 1st only
B.
December 31st only
C.
September 1 or December 31st
D.
June 1st or December 31st

A
sineoko [7]3 years ago
5 0

Answer:

A.   September 1st only.

Step-by-step explanation:

This question is based on assumptions.

Assumption 1st: Lets assume that the share was purchased on 1st January and all the other dates are also from the same year.

Assumption 2: In actual, the capital gain will be incurred if the share is sold on 1st September for $56. The gain will be of 56-45=11 dollars.

But if we sell the share on 31st December, then also we are gaining $2.

So, both can be the answer. September 1 or December 31st. But let us assume that the share was sold for maximum gain, then the answer will be option A.

Moreover it depends from person to person who is willing to sell in September or in December.

But technically it can be only September as it has maximum gain.

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112

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Someone please help!!
steposvetlana [31]

Answer:

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Step-by-step explanation:

Find the slope

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Another way to write it is

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3 years ago
Multiply: -14y(y+11)
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2 years ago
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Use the long division method to find the result when x^3+7x^2+12x+6x 3 +7x 2 +12x+6 is divided by x+1x+1. If there is a remainde
Aliun [14]

Answer:

By long division (x³ + 7·x² + 12·x + 6) ÷ (x + 1) gives the expression;

x^2 + 5 \cdot x + 7 - \dfrac{1}{(x + 1)}

Step-by-step explanation:

The polynomial that is to be divided by long division is x³ + 7·x² + 12·x + 6

The polynomial that divides the given polynomial is x + 1

Therefore, we have;

\ \ \ \ \ \  \ \ \ \ \ \ x^2 + 5\cdot x + 7\\ (x + 1) \sqrt{x^3 + 7\cdot x^2 +12\cdot x + 6} \\\ {} \  {} \ {}  \  \ {} \  {} \ {}  \ {} \  {} \ {}   \ {}     \ \ x^3 + 2 \cdot x^2 \\\  \ \ \ {} \   \ {} \  {} \ {}   \  \ {} \ {} \  \   \ {} \  {} \ {}  \  \ {} \  {} \ {}  \ \ 5 \cdot x^2 + 12\cdot x + 6\\  \ {} \  {} \ {}    \ {} \  {} \ {}  \ \ {} \ {} 5 \cdot x^2 + 5\cdot x\\\ 7\cdot x+6\\7\cdot x+7\\-1

(x³ + 7·x² + 12·x + 6) ÷ (x + 1) = x² + 5·x + 7 Remainder -1

Expressing the result in the form q(x) + \dfrac{r(x)}{b(x)}, we have;

(x^3 + 7\cdot x^2 + 12 \cdot x + 6)\div (x + 1) =  x^2 + 5 \cdot x + 7 - \dfrac{1}{(x + 1)}

4 0
2 years ago
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