Answer:
The answer is below
Step-by-step explanation:
Pythagoras theorem states that for a right angled triangle, the square of the hypotenuse side is equal to the sum of the square of the remaining sides. The hypotenuse is the longest side (that is side opposite to the 90° angle).
In right angle triangle ABD:
AB² = AD² + BD² (1)
In right angle triangle ACD:
AC² = AD² + CD² (2)
Also:
AC² + AB² = BC² (3)
But BC = BD + CD
AC² + AB² = (BD + CD)² (4)
Adding equation 1 and 2 gives:
AB² + AC² = (AD² + BD²) + (AD² + CD²)
AB² + AC² = 2AD² + BD² + CD²
substituting AC² + AB² = (BD + CD)²:
(BD + CD)² = 2AD² + BD² + CD²
BD² + 2(BD)(CD)+ CD² = 2AD² + BD² + CD²
2AD² = 2(BD)(CD)
AD² = BD * CD
Answer:
Step-by-step explanation:
1536(4)(4)=24576
Answer:
$295 ???
Step-by-step explanation:
A) 24
All side lengths of a square are equal so you take the square root of 576 to get two 24. If you try it back: 24*24 (w*h) to get 576.
Step-by-step explanation:
1. You already got the first step, where D is the midpoint of AC and AB is congruent to BC, since it's given.
2. AD will be congruent to DC, via the definition of a midpoint (a midpoint is the middle point of a line segment, and it splits the segment into two congruent parts)
3. BD is equal to BD, via reflexive property. ( It's a shared side between the two triangles)
4. that means that ΔADB ≅ΔCDB via SSS rule.
5. ∠ABD ≅∠CDB by CPCTC (corresponding parts of congruent triangles are congruent)
Hope this helps! :)
