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3 years ago

6

The sale price of a spring break vacation package is $209.99 the travel agent said by booking early, you saved $35. Find the per

cent decrease in price.

1 answer:

aleksandr82 [10.1K]3 years ago

6 0

Answer:

35%

Step-by-step explanation:

divide thirty five by 100 get thirty five precent

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2d+7/6-d-5/3=0 Tell me the answer

Inessa [10]

Answer:

d=1／2

Step-by-step explanation:

$2d + \frac{7}{6} - d - \frac{5}{3} = 0 \\ 2d - d = \frac{5}{3} - \frac{7}{6} \\ d = \frac{10}{6} - \frac{7}{6} \\ d = \frac{3}{6} \\ d = \frac{1}{2}$

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3 years ago

Solve for 5 points, will give brainlist

Elanso [62]

Answer:

i know that the first one is not equivlent but i dont know about the others

Step-by-step explanation:

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3 years ago

Explain how you could calculate the surface area of a<br> square pyramid.

lesya [120]

To find the surface area, use this square pyramid surface area formula: Square Pyramid Surface Area = 2 x B x S + B 2 B = Width of the Square Base S = Slant length of one of the triangular faces and is calculated from the height and base width by using the equation: S= The square root of [(.5B) 2 + Height 2] .

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3 years ago

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A circle has its center at the center of a square with 3-inch sides. Find the area of the square not covered by the circle Round

Aleonysh [2.5K]

So in order for us to know the area of the square that is not covered by the circle, we need to find first both the areas of the square and the circle.
So for the area of the square it is A = sxs. And for the circle is A = pi*r^2.
Let us find the area of the square first given that the side is 3 inches.
So A = 3*3
A = 9 square inches.
Next is the area of the circle. Since the center of the circle is the same with the center of the square, the radius would be 1.5.
SO, A = (3.14)(1.5)^2
A = 2.25 (3.14)
A = 7.065 square inches.
Next, we deduct the area of circle from area of square and the result would be 1.935 <span>in². So the answer for this would be option B.
Hope this answer helps.</span>

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3 years ago

Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

$\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$

We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}$

$=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}$

$=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}$

$=\frac{\sin\left(x\right)}{\cos\left(x\right)}$

$=\tan\left(x\right)$

Hence final answer is

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

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3 years ago