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Finger [1]
3 years ago
12

Solve and graph the equation x2+x-6=0

Mathematics
1 answer:
eimsori [14]3 years ago
3 0
Y=x²+x-6 (original form ax²+bx+c)

1) this is a parabola open upward since the coefficient of x² is positive
so it has a minimum.

2) Its symmetry line = -b/2a = -1/2 & for x=-1/2, y= 23/4
So its minimum is (-1/2, 23/4)

3) Now to see if the parabole intercepts the x-axis we calculate the roots of
x²+x-6. As you will notice Δ <0 so there is no roots & consequently it doesn't intersect with x-axis
Your graph is wrong, and the parabola should be above the x-axis & it will intersect with the y-axis at y=23/4 =5.75nunits


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20. What is the volume, in terms of r, for a cylindrical
inysia [295]

Step-by-step explanation:

Volume of cylindrical container

= \pi {r}^{2} h \\  \\  = 3.14 \times ( {3.25)}^{2}  \times 10 \\  \\  = 3.14 \times 10.5625 \times 10 \\  \\  = 331.6625  {cm}^{3}  \\  \\  \approx \: 331.66 \:  {cm}^{3}

4 0
3 years ago
Select all that apply <br> thαnkѕ pєrѕσn
vodka [1.7K]
Im gonna guess and say the right ones might be
A = AB or A'B'
B = CB or C'B'
D =  CA or C'A'
Cus all equal the same side
H0P3 It H2LPS :)
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8 0
2 years ago
Which graph represents a function? A coordinate plane shows 4 points with the following coordinates: (negative 3, 3), (negative
Jet001 [13]

The ordered pair that represents a function is:

⇒ (-3, 3), (-2, -2), (1, 1), (2, -2)

<u>What are Coordinates?</u>

A pair of numbers that describe the exact position of a point on a cartesian plane by using horizontal and vertical lines are called the coordinates.

The given points are;

(-3, 3), (-3, -3), (-1, 1), (1, 4)

(-3, 3), (-2, -2), (1, 1), (2, -2)

(-3, 3), (-3, -3), (1, -4), (1, 1)

(-4, 4), (-4, 1), (-2, 1), (2, 1)

Now, For an ordered pair to be a function, either of the following must be true:

Each x-value has exactly one corresponding y-value.

More than one x-values have the same corresponding y-values.

And, If any of the following conditions is true, then the ordered pair is not a function,

One x-value has multiple corresponding y-values.

More than one x-values have multiple corresponding y-values.

From the given options, only ordered pair  (-3, 3), (-2, -2), (1, 1), (2, -2) satisfies the condition to be a function.

Because none of its x-values have multiple corresponding y-values.

And, Other ordered pairs are either one-to-many or many-to-many.

So, The ordered pair that represents a function is:

⇒  (-3, 3), (-2, -2), (1, 1), (2, -2)

To learn more about ordered pairs visit:

brainly.com/question/19267542

#SPJ1

4 0
1 year ago
Find the length of side a.<br> 10<br> A<br> 6<br> A. 4<br> B. 64<br> C. V 136<br> D. 8<br> PREVIOUS
dedylja [7]

Answer:

D .8

Step-by-step explanation:

hypotenuse (h) = 10

base (b) = 6

perpendicular (p) = a= ?

We know by using Pythagoras theorem we get

p = √ h² - b²

a = √ 10² - 6²

a = √ 64

a = 8

Hope it will help :)

8 0
2 years ago
Consider the following statement. ∀ integer d, if 6 d is an integer then d = 3. Which of the following is a negation for the sta
omeli [17]

Answer:

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

Step-by-step explanation:

If 6d is an integer, then d = 3

Let's divide the statement into two:

Let "If 6d is an integer" be p and "then d = 3" be q.

The statement is a conditional statement. Therefore, we have

p ⇒ q

The negation of p ⇒q, ¬(p ⇒ q) ≡ p ∧ ¬q

I have attached an image proving the above.

Using this: ¬(p ⇒ q) ≡ p ∧ ¬q

Then, we leave p as it is and negate q.

P is "if 6d is an integer"

q is "then d = 3," hence ¬q is "then d ≠ 3."

Therefore, the negation of "If 6d is an integer, then d = 3" is "If 6d is an integer, then d ≠ 3."

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

6 0
2 years ago
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