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Mila [183]
3 years ago
5

Which number satisfies the inequality 9h + 15 > 55?

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
6 0
9h + 15 > 55
9h > 40
h > 40/9
telo118 [61]3 years ago
4 0
9h + 15 > 55
     - 15    - 15
9h > 40
h > 40/9
h > 4.44444.
any number greater than 4.44444
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lara31 [8.8K]

Answer:

f=\frac{9c}{5}+32

Step-by-step explanation:

c=\frac{5\left(f-32\right)}{9}

Switch sides:

\frac{5\left(f-32\right)}{9}=c

Multiply both sides by 9:

\frac{9\times5\left(f-32\right)}{9}=9c

5\left(f-32\right)=9c

Divide both sides by 5:

\frac{5\left(f-32\right)}{5}=\frac{9c}{5}

f-32=\frac{9c}{5}

Add 32 to both sides:

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8 0
4 years ago
How to solve d - 5 = 7 algebraically
adelina 88 [10]

Answer:

d = 12

Step-by-step explanation:

d - 5= 7

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d - 5 + 5 = 12

d = 12

6 0
3 years ago
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How do you solve this problem, ive been working for hours and just cant seem to get it. Help is very much aprrecieated.
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Answer:

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Step-by-step explanation:

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marusya05 [52]

Answer:

x^{2}=4y

y=\frac{1}{4}x^{2}

Step-by-step explanation:

Forma ordinaria

La ecuación de la parabola de manera ordinaria está dada por:

(x-h)^{2}=4p(y-k) (1)  

Donde:

  • (h,k) es la coordenda del vértice, en nuestro caso (0,0) ya que está en el origen.
  • (h,k+p) es la coordenda del foco, en nuestro caso (0,1).

Por lo tanto h = 0, k = 0 y p = 1.

Remplazando estos valores en la ecuación de la parábola, tenemos:

(x-0)^{2}=4*1(y-0)

x^{2}=4y (2)

 

Forma general  

La forma general de una parábola esta dada por la siquiente ecuación

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Reordenando la ecuación (2) tenemos:

y=\frac{1}{4}x^{2}

Espero esto te haya ayudado!

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