Answer:
In this case, the mass of the car and the force exerted on it are provided as information. Therefore, the acceleration of the car is 0.5 m s−2 when its engine exerts a force of 600 N
Step-by-step explanation:
Answer:
She get $16 dollars
Step-by-step explanation:
Hi there!
We can use right-triangle trigonometry to solve.
We are given the HYPOTENUSE and ADJACENT sides, so we must use cosine in this instance.
cosθ = Adjacent/Hypotenuse
We can plug in what is given:
cos(28) = A/17
Solve for 'A':
17cos(28) = <u>15.01 ft</u>
The value of csc C in fraction and in decimal form is as follows:
csc C = 5 / 3
csc C = 1.66666666667
Using trigonometric ratio,
secant A = 1 / cos A = hypotenuse / adjacent
Therefore,
sec A = 5/3
sec A = 1 / cos A
cos A = adjacent / hypotenuse
cos A = 3 / 5
A = cos⁻¹ 0.6
A = 53.1301023542
Therefore,
∠A = 53°
∠B = 90°
∠C = 180 - 143 = 37°
cosec C = 1 / sin C = hypotenuse / opposite
cosec C = 5 / 3
learn more about trigonometry here: brainly.com/question/25942962?referrer=searchResults
