There are 180 numbers which are three-digit multiples of 5.
According to the statement
we have to find the three digit numbers which are multiples of 5.
we know that three digit numbers are start from 100 to 999 and in 1 line of counting means 100 to 110 there are 2 numbers are multiples of 5.
Here we use Multiplication method to find the number of digit which are a multiple of 5.
It means there are two numbers which are multiples of 5 in the one line of counting and there are 90 lines of counting from 100 to 999.
So, it means the answer will become
2*90 = 180.
So, There are 180 numbers which are three-digit multiples of 5.
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Answer:
Whats your question
Step-by-step explanation:
PLZ MARK AS BRAINLIEST
Answer:
x = 2/5
General Formulas and Concepts:
Order of Operations: BPEMDAS
Step-by-step explanation:
<u>Step 1: Write equation</u>
5x = 2
<u>Step 2: Solve for </u><em><u>x</u></em>
- Divide both sides by 5: x = 2/5
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution</em>.
- Substitute: 5(2/5) = 2
- Multiply: 10/5 = 2
- Divide: 2 = 2
40.0*10 is the answer
actually it is 400 but u want in decimal so it is 40.0*10
No, they are both incorrect by my understanding of your question use the Pythagorean theorem a^2 + b^2 =c^, therefore, 7^2 +x^2 = 13^2 or 49+x=169 then solve normally 169-49=120 √120 =5
The answer is 5
