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kap26 [50]
2 years ago
11

No spam

Mathematics
2 answers:
Simora [160]2 years ago
5 0

Part A: Determine the test average for your math class after completing test 2. (2 points)

Part B: Determine the test average for your science class after the completing test 2. (2 points)

Part C: Which class had a higher average after completing test 4? Show work to support your answer. (6 points)

grigory [225]2 years ago
4 0

Table

\boxed{\begin{array}{c|c}\boxed{\bf x} &\boxed{\bf g(x)} \\ \sf 1&\sf 81 \\ \sf 2&\sf 83 \\ \sf 3&\sf 85\\ \sf 4 &\sf 87(Expected)\end{array}}

\boxed{\begin{array}{c|c}\boxed{\bf x} &\boxed{\bf f(x)} \\ \sf 1&\sf 80.5 \\ \sf 2&\sf 81 \\ \sf 3&\sf 81.5 \\ \sf 4&\sf 82\end{array}}

Now

#Part A:-

Test average for completing test 2 in maths=81

#Part-B

Test average for completing test 2in science=83

#Part C.

  • CLASS B HAS HIGHER AVERAGE
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Answer:

40,000,000

Step-by-step explanation:

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3 0
2 years ago
Jasmine, Abby, and Amber had $865 altogether. Jasmine spent 2/5 of her money. Abby spent $40, and Amber spent twice as much as J
erastovalidia [21]

Answer:

288.333333333

Step-by-step explanation:

Me, personally am not great with math, but I can say you have to take $865 then take away $40 then decide how much they get apiece. to do that you must divide 865 from 3. afterwards you should take that number away from 865 remember that you are also taking away 40 then you have your final answer

6 0
2 years ago
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nataly862011 [7]
You must first attach the problems with your question.
6 0
3 years ago
A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.
kipiarov [429]

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

C = Children; S = Students; A = Adults

For the capacity, we have:

C + S + A = 329

For the tickets sold, we have:

5C + 7S + 12A = 2388

Half as many as adults are children implies that:

A = \frac{C}{2}

Required

Solve for A, C and S

The equations to solve are:

C + S + A = 329 -- (1)

5C + 7S + 12A = 2388 -- (2)

A = \frac{C}{2} -- (3)

Make C the subject in (3)

C = 2A

Substitute C = 2A in (1) and (2)

C + S + A = 329 -- (1)

2A + S + A = 329

3A + S = 329

Make S the subject

S = 329 - 3A

5C + 7S + 12A = 2388 -- (2)

5*2A + 7S + 12A = 2388

10A + 7S + 12A = 2388

7S + 22A = 2388

Substitute S = 329 - 3A

7(329 - 3A) + 22A = 2388

2303 - 21A + 22A = 2388

2303 +A = 2388

Solve for A

A = 2388 - 2303

A = 85

Recall that: C = 2A

C = 2 * 85

C = 170

Recall that: S = 329 - 3A

S = 329 - 3 * 85

S = 329 - 255

S = 74

Hence, the result is:

C = 170

S = 74

A = 85

8 0
3 years ago
Please help me I need to turn in tomorrow please help me
Monica [59]

Answer:

<em>Answer: A. 0.2</em>

Step-by-step explanation:

<u>Probability</u>

The circle graph shows the distribution of the makeup of the Riverside Municipal Choir.

The total number of choir sections is: 8+10+10+12=40

To calculate the probability of a member chosen at random comes from the alto section, we use the formula:

\displaystyle P=\frac{8}{40}

Calculating:

P = 0.2

Answer: A. 0.2

7 0
2 years ago
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