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kap26 [50]
3 years ago
11

No spam

Mathematics
2 answers:
Simora [160]3 years ago
5 0

Part A: Determine the test average for your math class after completing test 2. (2 points)

Part B: Determine the test average for your science class after the completing test 2. (2 points)

Part C: Which class had a higher average after completing test 4? Show work to support your answer. (6 points)

grigory [225]3 years ago
4 0

Table

\boxed{\begin{array}{c|c}\boxed{\bf x} &\boxed{\bf g(x)} \\ \sf 1&\sf 81 \\ \sf 2&\sf 83 \\ \sf 3&\sf 85\\ \sf 4 &\sf 87(Expected)\end{array}}

\boxed{\begin{array}{c|c}\boxed{\bf x} &\boxed{\bf f(x)} \\ \sf 1&\sf 80.5 \\ \sf 2&\sf 81 \\ \sf 3&\sf 81.5 \\ \sf 4&\sf 82\end{array}}

Now

#Part A:-

Test average for completing test 2 in maths=81

#Part-B

Test average for completing test 2in science=83

#Part C.

  • CLASS B HAS HIGHER AVERAGE
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Answer:

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Step-by-step explanation:

A chocolate bar has a rectangular shape, therefore it's area is given by the following formula:

area = width*length

In this case the length is 0.7 feet longer than twice the width, therefore:

length = 2*width + 0.7

Applying the second equation on the first one and using the data from the question we have:

47.1 = width*(2*width + 0.7)

47.1 = 2*width² + 0.7*width

2*width² + 0.7*width = 47.1

width² + 0.35*width = 23.55

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width = 4.68099 or width = -5.03099

Since the width can't be negative, it can only be 4.68099 feet.

length = 2*4.68099 + 0.7 = 10.06198 feet.

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