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Paul [167]
3 years ago
9

Tell me what each angle is in the following triangle: angle 1 is 8x, angle 2 is 2x+3, angle 3: 30 degrees. give me the two answe

rs. *
Mathematics
1 answer:
dlinn [17]3 years ago
6 0
Could you find a way to share the illustration of this triangle?

Three angles are given:  8x, 2x+3 and 30 degrees. 

Use this rule:  the sum of the three angles of a triangle is 180 degrees.

Can you use this fact to solve for x?     By the way, I'm not convinced that there are 2 answers.  What makes you think there are 2?
You might be interested in
If TR=11 ft, find the length of PS
Klio2033 [76]

Answer:

PS = 31.5 ft

Step-by-step explanation:

∠PTS = 180 - 16 = 154°

164°(π/180) = 41π/45 radians

PS = rθ = 11(41π/45) = 31.48573...

5 0
2 years ago
Given f(x) = 2x^2 - 5x, determine the value of f(4).​
jeyben [28]

Answer:

12

Step-by-step explanation:

f(x) = 2x^2 - 5x

Let x=4

f(4) = 2 (4)^2 -5(4)

Exponents first

     = 2*16 -5*4

Multiply

     =32 -20

subtract

   =12

5 0
3 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
(AP Calc) the graph of the function f shown above has three line segments....
I am Lyosha [343]

Answer:

B

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ - 1, 6 ] and from the graph

f(b) = f(6) = 0

f(a) = f(- 1) = 0, thus

average rate of change = \frac{0-0}{6+1} = \frac{0}{7} = 0

7 0
3 years ago
Solve the equation. 1/4 = y/12. y=
charle [14.2K]

Answer:

Step-by-step explanation:

\frac{1}{4}=\frac{y}{12}\\\\\frac{1}{4}*12=y\\\\1*3=y\\\\y=3

8 0
3 years ago
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