Answer: 6 cajas de cada tipo de fruta.
Step-by-step explanation:
En cada caja de manzanas, tenemos 13 manzanas.
En cada caja de limones, tenemos 17 limones.
Si el numero total de cajas es C, entonces el numero total de manzanas es:
C*13
y el numero total de limones es: C*17.
Si en total tenemos 180 frutas, entonces tenemos que:
C*13 + C*17 = 180
C*(13 + 17) = 180
C*30 = 180
C = 180/30 = 6
Tenemos 6 cajas de cada tipo de fruta.
Since E is the midpoint, DE and EF are the same length.
Set the equation DE and EF equal to each other and solve for x.
2x + 4 = 3x - 1
x = 5
Then plug in 5 to find the length.
DE = 2(5) + 4 = 14
EF = 3(5) - 1 = 14
DF = DE + EF = 28
Answer: Example:The table shows the results of two surveys that randomly sampled 100 kids about their favorite types of pizza.
Pepperoni Cheese Supreme Total
Survey 1 3 7 16 26
Survey 2 9 13 4 26
Which statement can be made about kids' favorite types of pizza based on the information in the surveys?
Kids prefer cheese pizza more than other types of pizza.
Kids like supreme pizzas more than pepperoni pizzas.
Most kids do not like pepperoni on their pizzas.
More kids prefer pepperoni pizzas than other types of pizza.
Step-by-step explanation: Kids like supreme pizzas more than pepperoni pizzas. more chance of 16% or 4% of people getting chosen over the 26 total than 3% or 9%
<u>Step-By-Step Solution for Part 1:</u>
- 3(4p + 2) = 12p + 6
- => (3 x 4p) + (3 x 2) = 12p + 6
- => 12p + 6 = 12p + 6
Answer: Equivalent
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<u>Step-By-Step Solution for Part 2:</u>
Answer: Equivalent
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<u>Step-By-Step Solution for Part 3:</u>
- 2y + z² = y x y + z + z
- => 2y + z² = y² + 2z
<u>[Replacing y as 2 and z as 3]</u>
- => 2(2) + (3)² = (2)² + 2(3)
- => 4 + 9 = 4 + 6
- => 13 ≠ 10
Answer: Not Equivalent
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<u>Step-By-Step Solution for Part 4:</u>
15n + 5 = 5(3n + 1)
=> 15n + 5 = (5 x 3n) + (5 x 1)
=> 15n + 5 = 15n + 5
Answer: Equivalent
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Answer:
A, D, and F
Step-by-step explanation:
First off, we're not given the hypotenuse's length, so let's use the Pythagorean Theorem to find it:

With that, we can refer to SOH-CAH-TOA to help us find sine, cosine, and tangent:
SOH (Sine = Opposite/Hypotenuse)

CAH (Cosine = Adjacent/Hypotenuse)

TOA (Tangent = Opposite/Adjacent)

From this, we can see that A matches up with sine, and we can eliminate B and C.
Cosecant, secant, and cotangent are all reciprocals of the three basic trig ratios:

D matches with cosecant, and F matches with cotangent, so the correct trig rations for θ are A, D, and F.