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Natali [406]
2 years ago
15

How much will you lose

Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
4 0

Answer:

i don't know how much will l loose

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Perform the operation. 3/a^2b + 2/ab^2
Klio2033 [76]

The simplified form of the expression is 3b+2a/(ab)²

<h3>Sum of fractions</h3>

Fractions are written as a ratio of two integers. Given the expression below;

3/a^2b + 2/ab^2

Find the LCM

3/a^2b + 2/ab^2 = 3b+2a/a²b²

3/a^2b + 2/ab^2 = 3b+2a/(ab)²

Hence the simplified form of the expression is 3b+2a/(ab)²

Learn more on sum of fraction here: brainly.com/question/11562149

#SPJ1

5 0
2 years ago
How far does a bus travel at 2.5 hours at 65mph
oksian1 [2.3K]

the bus goes 65 miles every hour. so: 1hr = 65mi

to find how many miles it goes every 2.5 hours, we multiply each side by 2.5:

2.5hrs = 162.5mi

5 0
3 years ago
Read 2 more answers
Suppose that 30% of students prefer to write with a mechanical pencil. suppose we sample students, one at a time, and stop as so
tia_tia [17]
Probability that first student  prefers mechanical pen = 0.30
 P(first student does not and second student does) = 0.70 * 0.3 =  0.21)

P( selecting 2 or fweer) = 0.30+ 0.21) = 0.51  or 51%
6 0
3 years ago
F(x)=Tan^-1 (1)<br><br> PLEASE ANSWER! WILL GIVE BRAINLIEST
notka56 [123]

Answer:

−π

----

4

Step-by-step explanation:

Alright, archtan /

tan

−

1

(

x

)

is the inverse of tangent. Tan is

sin

cos

. Like the inverse of sin, the inverse of tan is also restricted to quadrants 1 and 4.

Knowing this we are solving for the inverse of tan -1. We are basically being asked the question what angle/radian does tan(-1) equal. Using the unit circle we can see that tan(1)= pi/4.

Since the "Odds and Evens Identity" states that tan(-x) = -tan(x). Tan(-1)= -pi/4.

Knowing that tan is negative in quadrants 2 and 4. the answer is in either of those two quadrants. BUT!!! since inverse of tan is restricted to quadrants 1 and 4 we are left with the only answer -pi/4.

5 0
3 years ago
Solve the inequality |6x + 2| &lt; 10 and graph its solution.
mars1129 [50]
This is a modulus inequality.
First part: when (6x + 2) is positive
6x + 2 < 10
6x < 10 - 2
6x < 8
x < 8/6
x < 4/3

Second part: when (6x + 2) is negative.

-(6x + 2) < 10   Divide both sides of inequality by -1 and change the sign.

  (6x + 2) > -10
   6x + 2 > -10
   6x > -10 - 2
   6x > -12        Divide both sides by 6.
     x > -12/6
     x > -2.

Combined solution:   x < 4/3  and x > -2

  -2 < x < 4/3.

Graph is a line on the number line between -2 and 4/3.  
 
-2 and 4/3 are excluded from solution.
8 0
3 years ago
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