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dimaraw [331]
3 years ago
9

PLZ answer quick!!!!!

Mathematics
1 answer:
Blizzard [7]3 years ago
3 0

Number of items sold by Shelley = 3 items.

Let us assume cost of each item sold by Shelley = $ x each.

Total cost of 3 items for Shelly sold = 3*x = 3x.

Number of items sold by Billy Bob = 4 items.

The cost of each item sold by Billy Bob = $2.25 less than the items that Shelley bought = $(x-2.25) each.

Total cost of 4 items for Billy Bob sold = 4*(x-2.25) = 4(x-2.25).

Both Shelley and Billy Bob paid the same amount of money. So, we can setup an equation now.

a) Total cost of 4 items for Billy Bob sold=Total cost of 3 items for Shelly sold.

4(x-2.25) = 3x

b) Solving equation for x now.

Distributing 4 over (x-2.25), we get

4x - 4*2.25 = 3x.

4x -9 = 3x.

Adding 9 on both sides, we get

4x -9+9 = 3x+9

4x =3x+9.

Subtracting 3x from both sides, we get

4x-3x =3x-3x+9.

x = 9.

c) Checking the solution of the equation by plugging x=9 in equation we got above.

4(x-2.25) = 3x  => 4(9-2.25)= 3*9

               => 4*6.75 = 27

               => 27 = 27.

We got left side = right side. So the solution x=9 is correct.

d) The cost of each item sold by Billy Bob = 9-2.25 = $6.75

Therefore, the cost of each item sold by Shelley is $9 and cost of each item sold by Billy Bob is $6.75.

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The flour bought in August = \frac{3}{4} × The flour bought in January. From the table, we have the flour bought in January was 3 pounds.

The flour bought in August = \frac{3}{4} × 3 = \frac{9}{4} = 2\frac{1}{4} pounds. (9 divided by 2 gets a quotient of 2 and remainder 1)

Step 2; She bought \frac{7}{8} as much in April as she did in both October and July.

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The flour bought in October and July = \frac{3}{4} + 1\frac{1}{4} = \frac{3}{4} + \frac{5}{4} = \frac{8}{4} = 2 pounds.

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The flour bought in August = 2 × \frac{8}{7} = \frac{16}{7} = 2\frac{2}{7} pounds. (16 divided by 7 gets a quotient of 2 and remainder 2)

3 0
3 years ago
HURRY PLZ!!!!!!
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