The zeroes of the polynomial functions are as follows:
- For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
- For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
- For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
<h3>What are the zeroes of a polynomial?</h3>
The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.
The polynomials are given as follows:
f(x) = 2x(x - 3)(2 - x)
f(x) = 2(x - 3)²(x + 3)(x + 1)
f(x) = x³(x + 2)(x - 1)
For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.
Learn more about polynomials at: brainly.com/question/2833285
#SPJ1
Factor the denominator:
(3x-1)(x+2)
every time x=-2 (because of (x+2), it would cause a warp in the graph, and not have an input. that is the vertical asymptote.
since you have factor 3x-1 on top and bottom, in which the zero is 1/3, there would be no solution at x=1/3. it would be a hole.
the answer here is C.
Answer:
x = -2
y = 3
Step-by-step explanation:
-5x + 3y = 19
x = 3y - 11
-5x + 3y = 19
-5(3y - 11) + 3y = 19
-15y + 55 + 3y = 19
-15y + 3y + 55 = 19
-12y + 55 = 19
-12y = 19 - 55
-12y = -36
y = -36/-12
<u>y = 3</u>
x = 3y - 11
x = 3(3) - 11
x = 9 - 11
<u>x = -2</u>
Answer:
20%
Step-by-step explanation:
Answer:
$35
Step-by-step explanation:
175/5 = 35
have a nice day! (maybe get this double checked in case I did it wrong :D)
