Perpendicular sides or lines meet at right angles. The conclusion that can be reached is that:
<em>1. all of the rings are perpendicular to that side.</em>
The statements in the question can be listed as:
- <em>Rings in the ladder are parallel</em>
- <em>Top ring is perpendicular to the side of the ladder</em>
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From statements 1 and 2 above, we understand that;
<em>All other rings in the ladder are parallel to the side ring</em>
This means that the relationship between the top ring and the side of the ladder is the same as the relationship between other rings and the side of the ladder
i.e. the side rings are also perpendicular to the side of the ladder
Hence, the conclusion that can be reached is:
<em>1. all of the rings are perpendicular to that side.</em>
Read more about parallel and perpendicular sides at:
brainly.com/question/8607613
Answer:
0.362
Step-by-step explanation:
When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:
- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.
- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14
- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7
- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.
Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability
P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362
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Answer:
Below
Step-by-step explanation:
Because it is $7 per day and x = the length of rental days, our equation will look something like this :
y = 7x + 3
Hope this helps!
Well to find out X, you have to do the opposite to what it's asking to each side. So 11=x-4
+4 onto the 11 and + 4 on to the -4 which means you just have 15=X
