All categories

3 years ago

Help if u know the answer

Mathematics

1 answer:

Fiesta28 [93]3 years ago

6 0

$( \frac{a}{b} )( \frac{c}{d} )= \frac{ac}{bd}$ so
$( \frac{3}{10} )( \frac{-4}{5} )= \frac{3*-4}{10*5}= \frac{-12}{50}= \frac{-6}{25}$

You might be interested in

Select the pair of equations whose graphs are perpendicular.

viktelen [127]

$k:\ y=m_1x+b_1\ \ \ \ and\ \ \ \ l:\ y=m_2x+b_2\\ \\the\ line\k\ is\ perpendicular\ to\ the\ line\ l\ \ \ \Leftrightarrow\ \ \ m_1\cdot m_2=-1\\----------------------------\\\\A.\\2y=-3x+5\ \ \Rightarrow\ \ \ y=- \frac{3}{2} x+2.5\ \ \Rightarrow\ \ m_1=- \frac{3}{2} \\\\2x+3y=4\ \ \Rightarrow\ \ 3y=-2x+4\ \ \Rightarrow\ \ y=- \frac{2}{3}x+1 \frac{1}{3} \ \ \Rightarrow\ \ m_2=- \frac{2}{3} \\\\m_1\cdot m_2=- \frac{3}{2} \cdot (- \frac{2}{3})=1 \neq -1$

$B.\\5x-8y=9\ \ \Rightarrow\ \ -8y=-5x+9\ \ \Rightarrow\ \ \ y= \frac{5}{8} x-1 \frac{1}{8} \ \Rightarrow\ \ m_1= \frac{5}{8} \\\\12x-5y=7\ \Rightarrow\ \ -5y=-12x+7\ \ \Rightarrow\ \ y= \frac{12}{5}x-1 \frac{2}{5} \ \ \Rightarrow\ \ m_2= \frac{12}{5} \\\\m_1\cdot m_2= \frac{5}{8} \cdot \frac{12}{5}= \frac{3}{2} \neq -1$

$C.\\y=2x-7\ \ \Rightarrow\ \ m_1=2 \\\\x+2y=3\ \Rightarrow\ \ 2y=-x+3\ \ \Rightarrow\ \ y= -\frac{1}{2}x+1 \frac{1}{2}\ \ \Rightarrow\ \ m_2=- \frac{1}{2} \\\\m_1\cdot m_2= 2 \cdot (- \frac{1}{2})= -1\ \ \Rightarrow\ \ y=2x-7\ \ \ \ \perp\ \ \ \ x+2y=3$

$
D.\\x+6y=8\ \ \Rightarrow\ \ 6y=-x+8\ \ \Rightarrow\ \ \ y=- \frac{1}{6} x+1 \frac{1}{3}\ \ \Rightarrow\ \ m_1= -\frac{1}{6} \\\\y=2x-8\ \Rightarrow\ \ m_2= 2 \\\\m_1\cdot m_2= -\frac{1}{6} \cdot2=- \frac{1}{3} \neq -1$

7 0

3 years ago

What expression equals to 3^15

GuDViN [60]

Answer:

14348907

Step-by-step explanation:

That's the right answer

8 0

3 years ago

Read 2 more answers

If two lines are perpendicular, what must be true about the slopes of the two lines. Select all that apply.

bazaltina [42]

Answer:

Concept: Linear Systems

Those that are parallel have equal slope, contrary those that are parallel have reciprocal.
Hope this helps!

7 0

3 years ago

WILL MARK BRAINLIEST - 75 POINTS!!

Tpy6a [65]

Answer:

$(10x-1)^2$

Step-by-step explanation:

Here we are going to apply the rule of "Square of the difference". The rule is as given below

$(a-b)^2=a^2-2 \times a \times b + b^2$ ---------(A)

Now we have our original polynomial as

$100x^2-20x+1$

Which can be re written as

$(10x)^2-2 \times 10x \times 1 + 1^2$ ---------------(B)

Hence comparing it with (A)

$a=10x$

$b=1$

Applying the rule on (B)

$(10x)^{2}-2 \times 10x \times 1 + 1^2 = (10x-1)^2$

Hence our answer is

$(10x-1)^2$

6 0

3 years ago

Read 2 more answers

Given that line t is the perpendicular bisector of JK and GK=8.25 find GJ

Paraphin [41]

1. As you can see in the figure attached, the <span> line "t" is the perpendicular bisector of JK, and divides the triangle in two equal right triangles. This means that both triangles are congruent. Therefore, both have equal dimensions. Keeping this on mind, you have the followiig:

2. Both triangles are congruents, then:

GK=GJ

3. So if the lenght GK is 8.25, the length GJ has the same length:

GJ=8.25

4. Therefore, the answer is:

GJ=8.25</span>

5 0

4 years ago