1. Let's call:
x: the width of the walkway.
b: 2x+16 (there is a widht "x" of the walkway on each side).
h: 2x+32 (there is a widht "x" of the walkway on each side).
A: 924 ft^2 ( the area of the pool of including the walkway).
2. The area of a rectangle is:
A=(b)(h)
b: the base of the rectangle (2x+16)
a: the height of the rectangle (2x+32)
3. Then, we have a quadratic equation:
924=(2x+16)(2x+32)
4x^2+64x+32x+512-924=0
4x^2+96x-412=0
4. We apply the quadratic formula to find the value of "x":
x=(-b±√(b^2-4ac))/2a
x=3.71
The answer is: The width of the walkway is 3.71 ft
Answer:
C
Step-by-step explanation:
m = -3
y = mx +b
y = -3x + b
Plugin x = -1 and y = 4
4 = -3*(-1) +b
4 = 3 + b
4-3 = b
b = 1
y = -3x + 1
Answer:
A function with a positive constant other than 1 raised to a variable exponent.
Step-by-step explanation:
Answer:
6.39 pounds, 102.29 ounces.
Step-by-step explanation:
