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WARRIOR [948]
3 years ago
9

Please help with #9 i’ll be giving a brainliest to the person with the correct answer

Mathematics
1 answer:
ikadub [295]3 years ago
4 0

Answer: y= -5x+7 hehe its right

Step-by-step explanation:

y=mx+b

y=-5x+7

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Find the measures of the angles in each triangle <br> 2xº<br> 3x°<br> xº
snow_lady [41]

Answer:

x = 30°

The angles:

  • 2x° = 60°
  • 3x° = 90°
  • x° = 30°

Step-by-step explanation:

Hello!

The sum of all the angles in a triangle is 180°. So we can set up an equation for this question.

Solve the equation:

  • 2x° + 3x° + x° = 180°
  • 6x° = 180°
  • x° = 30°

We can replace 30° for all the angles.

The measures are:

  • 2(30°) = 60°
  • 3(30°) = 90°
  • 1(30°) = 30°

4 0
2 years ago
Read 2 more answers
The distance between City A and City B is 250 miles. A length of 2.1 feet represents this distance on a certain wall map. City C
tigry1 [53]

Answer:

650 miles

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

5 0
3 years ago
Read 2 more answers
Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
3 years ago
Use the picture below to find the length of x. Round your answer to the nearest hundredth.
valentinak56 [21]

Answer: 6.71

=======================================

Work Shown:

The longest horizontal portion of length 6 breaks up into two equal pieces of length 3 each. Focus on the smaller right triangle on the right hand side. This right triangle has legs of 3 and 6. The hypotenuse is x.

Use the pythagorean theorem with a = 3, b = 6, c = x to find the value of x

a^2 + b^2 = c^2

3^2 + 6^2 = x^2

9 + 36 = x^2

45 = x^2

x^2 = 45

x = sqrt(45)

x = 6.7082039

x = 6.71

4 0
3 years ago
Divide. check your answer
slava [35]

Step-by-step explanation:

:)..................

7 0
2 years ago
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