Answer:
6
Step-by-step explanation:
30 divided by 5=6
ur welcome ;)
As given;
2.52x10^7 people are living in <span>4.05x10^5 km^2 area. then for 1km^2, the number of people can be calculated as:
people in 1km^2 = (2.52x10^7) / (</span><span>4.05x10^5)
=0.62x10^2
or
=6.2x10^1</span>
Answer:
The 5x^2 vs -5x^2 will reflect over "X" axis
the +1 vs -2 will shift the graph down three units
the first answer is the correct answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
![x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\](https://tex.z-dn.net/?f=x%5E2%2By%5E2-8x%2B4y%2B4%3D0%5C%5C%5C%5Ca%29%5C%5C%5C%5Cx%5E2-8x%2By%5E2%2B4y%2B4%3D0%5C%5C%5C%5Cx%5E2-2%2Ax%2A4%2B%28y%5E2%2B2%2Ay%2A2%2B2%5E2%29%3D0%5C%5C%5C%5Cx%5E2-2%2Ax%2A4%2B4%5E2%2B%28y%2B2%29%5E2%3D4%5E2%5C%5C%5C%5C%28x-4%29%5E2%2B%28y%2B2%29%5E2%3D4%5E2%5C%5C)
Hence,
The radius of the circle is 4 units, coordinates of its centre are (4,-2).
![b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3} \\\sqrt{D}=4\sqrt{3} \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}](https://tex.z-dn.net/?f=b%29%5C%5C%5C%5Cy%3D0%5C%5Cx%5E2%2B0%5E2-8x%2B4%2A0%2B4%3D0%5C%5Cx%5E2-8x%2B4%3D0%5C%5Ca%3D1%5C%20%5C%20%5C%20%5C%20b%3D-8%5C%20%5C%20%5C%20%5C%20c%3D4%5C%5CD%3D%28-8%29%5E2-4%2A1%2A4%5C%5CD%3D64-14%5C%5CD%3D48%5C%5C%5Csqrt%7BD%7D%3D%5Csqrt%7B48%7D%20%5C%5C%20%5Csqrt%7BD%7D%3D%5Csqrt%7B16%2A3%7D%20%5C%5C%5Csqrt%7BD%7D%3D%5Csqrt%7B4%5E2%2A3%7D%20%20%5C%5C%5Csqrt%7BD%7D%3D4%5Csqrt%7B3%7D%20%20%5C%5C%5Cdisplaystyle%5C%5Cx%3D%5Cfrac%7B-%28-8%29%D0%B14%5Csqrt%7B3%7D%20%7D%7B2%2A1%7D%20%5C%5C%5C%5Cx%3D%5Cfrac%7B8%D0%B14%5Csqrt%7B3%7D%20%7D%7B2%7D%20%5C%5Cx_1%3D4-2%5Csqrt%7B3%7D%20%5C%5Cx_2%3D4%2B2%5Csqrt%7B3%7D)
![c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16](https://tex.z-dn.net/?f=c%29%5C%5C%5C%5CA%286%2C2%5Csqrt%7B3%7D-2%29%5C%5C%20%28x-4%29%5E2%2B%28y%2B2%29%5E2%3D4%5E2%5C%5C%286-4%29%5E2%2B%282%5Csqrt%7B3%7D%20-2%2B2%29%5E2%3D16%5C%5C2%5E2%2B%282%5Csqrt%7B3%7D%20%29%5E2%3D16%5C%5C4%2B2%5E2%2A%28%5Csqrt%7B3%7D%29%5E2%3D16%5C%5C%204%2B4%2A3%3D16%5C%5C4%2B12%3D16%5C%5C16%5Cequiv16)
![d)\\A(6,2\sqrt{3}-2)}\\\sqrt{3} x+3y=\\\sqrt{3}(6)+3(2\sqrt{3} -2)=\\ 6\sqrt{3}+6\sqrt{3} -6=\\ 12\sqrt{3}-6](https://tex.z-dn.net/?f=d%29%5C%5CA%286%2C2%5Csqrt%7B3%7D-2%29%7D%5C%5C%5Csqrt%7B3%7D%20x%2B3y%3D%5C%5C%5Csqrt%7B3%7D%286%29%2B3%282%5Csqrt%7B3%7D%20-2%29%3D%5C%5C%206%5Csqrt%7B3%7D%2B6%5Csqrt%7B3%7D%20-6%3D%5C%5C%2012%5Csqrt%7B3%7D-6)