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soldi70 [24.7K]
3 years ago
14

The rate at which water is sprayed on a field of vegetables is given by R(t)=2sqrt(1+5t^3), where t is in minutes and R(t) is in

gallons per minute. During the time interval 0 to 4 inclusive, what is the average rate of water flow, in gallons per minute?
Mathematics
1 answer:
Lunna [17]3 years ago
8 0
<span>The formula is 1/b-a int(equation) from zero to four. Just integrate normally and multiply by the first part.
</span><span>integrate with limits 0,4 then divide by 4
</span>
<span>1÷4 (limit o to 4)∫ 2√1+5t^3 dt
= </span><span>14.691</span>
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I need help!!!!!!!!!
Natalka [10]

Answer:

10 2/3 x 9/10 = 9 3/5

1 x 10 2/3 = 10 2/3

10 2/3 x 2 1/3 = 24 8/9

1/8 x 10 2/3 = 1 1/3

10 2/3 x 3/5 = 6 2/5.

Hope this helps!

8 0
2 years ago
The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest
Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)

Calculation the value from standard normal z table, we have,  

P(x < 5) =0.7287= 72.87\%

b) P( port handles 3 or more million tons of cargo per week)

P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)

Calculating the value from the standard normal table we have,

1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%

c)P( port handles between 3 million and 4 million tons of cargo per week)

P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%

P(3 \leq x \leq 4) = 23.7\%

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85  

= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85  

=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15  

Calculation the value from standard normal z table, we have,  

P( z \leq -1.036) = 0.15

\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0
3 years ago
4:3 and 25:45 are equal ratios. True or false ?
gregori [183]
False. When simplified, 25:45 is equal to 5:9. Therefore, the two ratios are not equal
6 0
4 years ago
In a sample of 62 cups, the average diameter was found to be 3.07in. with a standard deviation of 0.21. Give a point estimate fo
Marina CMI [18]

Answer:

Population standard deviation (σ) = 0.3 in

Step-by-step explanation:

Sample mean = 3.07 in

Sample standard deviation (s) = 0.21 in

Sample size (n) = 62 cups

Population standard deviation (σ) = ?

The point estimate for the population standard deviation is given by sample standard deviation divided by the square root of the sample size:

\sigma = \frac{s}{\sqrt{n}}\\\sigma = \frac{0.21}{\sqrt{62}}\\\sigma = 0.03\ in

6 0
3 years ago
A 2-digit number is one more than 6 times the sum of its digits. If the digits are reversed, the new number is 9 less than the o
kramer

Answer:

I think the answer is 43

8 0
3 years ago
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