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Vanyuwa [196]
4 years ago
6

In recent years, 23.8% of all registered doctors were female. If there were 57,800 female registered doctors that year, what was

the total number of registered doctors?
Mathematics
1 answer:
PilotLPTM [1.2K]4 years ago
6 0
57,800 is 23.8% of the total number of registered doctors.

To find out the number of registered doctors, we divide the number of female doctors by 23.8% as a decimal (which is just 0.238):

57,800 ÷ 0.238 = 242,857
-------------------------------------------------------------------------------------------------------------
Answer:

So there are 242,857 registered doctors.
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A football player runs 13 1/2 yards how many feet does he run?
elixir [45]

Answer:

40 and a half feet

Step-by-step explanation:

1 meter=3 feet

13.5m=40.5f

3 0
3 years ago
Need help with this
ivolga24 [154]

In a triangle, the sum of the interior angles is 180.

So, you have

A+B+C=180

Plug the values for angles A and C:

75+B+20=180 \iff 95+B=180 \iff B=180-95=85

6 0
3 years ago
My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the
AVprozaik [17]

Answer:

a) n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

b) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.9=0.1 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

8 0
3 years ago
I need to find the formula for these shaded squares
vaieri [72.5K]

For the given sequence we have the formula:

Sₙ = 1 + (n - 1)*2

The 50th square will have 99 shaded squares.

<h3 /><h3>How many shaded squares are on the n-th square?</h3>

Here we have a sequence:

The first square has 1 shaded squares.

the second square has 3 shaded squares.

The third square has 5 shaded squares.

And so on.

Already you can see a pattern here, each next step we add 2 shaded squares, then we can write the formula:

Sₙ = 1 + (n - 1)*2

Where S is the number of shaded squares and n is the number of the figure.

Then the 50th square will have:

S₅₀ = 1+ (50 - 1)*2  1 + 49*2 = 99

Learn more about sequences:

brainly.com/question/6561461

#SPJ1

8 0
1 year ago
Based on the demand graph and the supply graph shown above, what is the price at the point of equilibrium?
Vesna [10]

B. 70

I took the test on Edge 2022

8 0
3 years ago
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