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KATRIN_1 [288]
4 years ago
7

How to simplify the fractions

Mathematics
1 answer:
AURORKA [14]4 years ago
4 0

Answer:

\large\boxed{\dfrac{3x+6}{x-4}\div\dfrac{2x^2+9x+10}{x^2+4x}=\dfrac{3x(x+4)}{(x-4)(2x+5)}}

Step-by-step explanation:

Just like that

\dfrac{3x+6}{x-4}\div\dfrac{2x^2+9x+10}{x^2+4x}=\dfrac{3x+6}{x-4}\cdot\dfrac{x^2+4x}{2x^2+9x+10}\\\\=\dfrac{3(x+2)}{(x-4)}\cdot\dfrac{x(x+4)}{2x^2+4x+5x+10}=\dfrac{3(x+2)}{(x-4)}\cdot\dfrac{x(x+4)}{2x(x+2)+5(x+2)}\\\\=\dfrac{3(x+2)}{(x-4)}\cdot\dfrac{x(x+4)}{(x+2)(2x+5)}\qquad\text{cancel}\ (x+2)\\\\=\dfrac{3x(x+4)}{(x-4)(2x+5)}

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Step-by-step explanation:

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Step 2: Divide both sides by -2x.

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Answer:

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———————————————————

Let's solve for x.

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Step 1: Add -10 to both sides.

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Step 2: Divide both sides by -2b.

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